[C++知识库]leetcode412Fizz Buzz

思路

1. c语言里没有整数转字符串的，需要手动写，而且要反转一次
2. 注意i是从1开始的，数组是从0开始

代码

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

void exchange(char *s){
    int i=0,j = strlen(s)-1;
    while (i<j)
    {
        char temp ;
        temp =s[i];
        s[i] =s[j];
        s[j] =temp;
        i++;j--;
    }
    
}

char * inttostring(int a){
    char *r = (char*)malloc(32);
    int i=0;
    if(a<0){
        r[i++] = '-';
    }
    while (a)
    {
        int temp = a%10;
        r[i++] = temp+48;
        a= a/10;
    }
    r[i] = '\0';
    exchange(r);
    return r;
}

char ** fizzBuzz(int n, int* returnSize){
    char **re = (char **)malloc(sizeof(char*)*n);
    int i;
    for(i=0;i<n;i++)
        re[i] = (char*)malloc(n);
    for(i=1;i<=n;i++){
        if(i%3==0&&i%5==0)
            re[i-1] = "FizzBuzz";
        else if(i%5==0)
            re[i-1] = "Buzz";
        else if(i%3==0)
            re[i-1] = "Fizz";
        else
            re[i-1]=inttostring(i);
    }
    *returnSize = n;
    return re;
}


int main(){
    int a = 15;
    int size = 0;
    int i;
    char ** re = fizzBuzz(a,&size);
    for(i=0;i<size;i++)
        printf("%s\n",re[i]);  
}