[C++知识库]值传递与地址传递（C++）

值传递不会改变实参

地址传递会改变实参

#include <iostream>
using namespace std;
void swap1(int a ,int b)
{
    int temp = a;
    a = b;
    b = temp;
}
//地址传递
void swap2(int * p1, int *p2)
{
    int temp = *p1;
    *p1 = *p2;
    *p2 = temp;
}

int main() {

    int a = 10;
    int b = 20;
    swap1(a, b); // 值传递不会改变实参

    cout << "a = " << a << endl;

    cout << "b = " << b << endl;

    swap2(&a, &b); //地址传递会改变实参

    cout << "a = " << a << endl;

    cout << "b = " << b << endl;

    return 0;
}

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