[C++知识库]PATA1135_c++基础（难度：??）

没难度上代码。

#include <bits/stdc++.h>
using namespace std;
vector<string> ans;
int main() {
    int n;
    string name, pw;
    scanf ("%d", &n);
    for (int i = 0; i < n; i++) {
        int flag = 0;
        cin >> name >> pw;
        for (int j = 0; j < pw.size(); j++) {
            switch (pw[j]) {
                case '1': pw[j] = '@'; flag = 1; break;
                case '0': pw[j] = '%'; flag = 1; break;
                case 'l': pw[j] = 'L'; flag = 1; break;
                case 'O': pw[j] = 'o'; flag = 1; break;
            }
        }
        if (flag == 1) ans.push_back (name + " " + pw);
    }
    if (ans.size() == 0) {
        if (n == 1) printf ("There is 1 account and no account is modified");
        else printf ("There are %d accounts and no account is modified", n);
        return 0;
    }
    printf ("%d\n", ans.size());
    for (int i = 0; i < ans.size(); i++) 
        printf ("%s\n", ans[i].c_str());
}