[C++知识库]根据节点值求父节点（C语言）

#include<stdio.h>
#include<stdlib.h>
struct TreeNode{
    int data;
    struct TreeNode *left;
    struct TreeNode *right;
};
struct TreeNode *createNode(int num){
    struct TreeNode *T;
    T=(struct TreeNode *)malloc(sizeof(struct TreeNode));
    T->left=NULL;
    T->right=NULL;
    T->data=num;
    return T;
}
struct TreeNode *createTree(struct TreeNode *T,int num){
    if(T==NULL){
        return createNode(num);
    }
    if(T->data>num){
        T->left=createTree(T->left,num);
    }else if(T->data<num){
        T->right=createTree(T->right,num);
    }
    return T;
}
struct TreeNode *Parent(struct TreeNode *T,int key,int height){/*求父节点的核心代码*/
    if(T==NULL||(height==1&&T->data==key)){
        return NULL;
    }
    if(T->left!=NULL&&T->left->data==key||T->right!=NULL&&T->right->data==key){
        return T;
    }
    struct TreeNode *temp;
    temp=Parent(T->left,key,height+1);
    if(temp!=NULL){
        return temp;
    }else{
        return Parent(T->right,key,height+1);
    }
}
void preOrder(struct TreeNode *T){
    if(T!=NULL){
        printf("\t%d",T->data);
        preOrder(T->left);
        preOrder(T->right);
    }
}
void inOrder(struct TreeNode *T){
    if(T!=NULL){
        inOrder(T->left);
        printf("\t%d",T->data);
        inOrder(T->right);
    }
}
void postOrder(struct TreeNode *T){
    if(T!=NULL){
        postOrder(T->left);
        postOrder(T->right);
        printf("\t%d",T->data);
    }
}
int main(){
    struct TreeNode *T,*re;
    T=NULL;
    for(int i=1;i<6;i++){
        T=createTree(T,i);    }
    printf("二叉树:\n前序遍历:");
    preOrder(T);
    printf("\n中序遍历:");
    inOrder(T);
    printf("\n后序遍历:");
    postOrder(T);
    int key=4;
    re=Parent(T,key,1);
    printf("\n值为4的节点的父节点值为:");
    if(re){
        printf("%d",re->data);
    }else{
        printf("NULL");
    }
    return 0;
}

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