[C++知识库]C++多重继承的虚函数表

#include <iostream>

using namespace std;

class Father {
public:
	virtual void func1() { cout << "Father::func1" << endl; }
	virtual void func2() { cout << "Father::func2" << endl; }
	virtual void func3() { cout << "Father::func3" << endl; }
	void func4() { cout << "非虚函数：Father::func4" << endl; }
public:
	int x = 200;
	int y = 300;
	static int z;
};

class Mother {
public:
	virtual void handle1() { cout << "Mother::handle1" << endl; }
	virtual void handle2() { cout << "Mother::handle2" << endl; }
	virtual void handle3() { cout << "Mother::handle3" << endl; }
public: //为了便于测试，使用public权限
	int m = 400;
	int n = 500;
};

class Son : public Father, public Mother {
public:
	void func1() { cout << "Son::func1" << endl; }
	virtual void handle1() { cout << "Son::handle1" << endl; }
	virtual void func5() { cout << "Son::func5" << endl; }
};

int Father::z = 0;

typedef void(*func_t)(void);

int main(void) {
	Son son;
	int* vptr = (int*) * (int*)&son;
	cout << "第一个虚函数表指针：" << vptr << endl;

	for (int i = 0; i < 4; i++) {
		cout << "调用第" << i + 1 << "个虚函数:";
		((func_t) * (vptr + i))();
	}

	for (int i = 0; i < 2; i++) {
		cout << *(int*)((int)&son + 4 + i * 4) << endl;
	}

	int* vptr2 = (int*) * ((int*)&son + 3);
	for (int i = 0; i < 3; i++) {
		cout << "调用第" << i + 1 << "个虚函数:";
		((func_t) * (vptr2 + i))();
	}

	for (int i = 0; i < 2; i++) {
		cout << *(int*)((int)&son + 16 + i * 4) << endl;
	}

	system("pause");
	return 0;
}

执行结果

VS分析：

内存分布