[C++知识库]C++将二维数组转置

第一种:N＊N列矩阵

#include <iostream>
#define N 3
using namespace std;

void ReverseArray(int a[N][N]){//数组转置
    int t;
    for(int i = 0; i < N; i++){
        for(int j = i; j < N; j++){
            if(i != j){//主对角线上的数组转之后为本身,所以进行交换
                t=a[i][j];a[i][j]=a[j][i];a[j][i]=t;
            }
        }
    }
}
int main() {
    int a[N][N] = {{1,2,3},{4,5,6},{7,8,9}};
    cout<<"原始数组:\n";
    for(int i = 0; i < N; i++){//打印数组
        for(int j = 0; j < N; j++){
            cout<<a[i][j]<<" ";
        }
        cout<<endl;
    }
    ReverseArray(a);
    cout<<"\n转置后的数组为：\n";
    for(int i = 0; i < N; i++){//转置数组
        for(int j = 0; j < N; j++){
            cout<<a[i][j]<<" ";
        }
        cout<<endl;
    }
    
    return 0;
}

第二种：N＊M列矩阵
只改动了一点,在转置的时候补全整个矩阵

#include <iostream>
#define N 3
#define M 4
using namespace std;

void ReverseArray(int a[N][M]){//数组转置
    int t;
    int m = M>N?M:N;
    //这里的思路是取M和N的最大值，补全整个m*m矩阵然后再进行转置
    //在输出的时候输出M＊N
    for(int i = 0; i < m; i++){
        for(int j = i; j < m; j++){
            if(i != j){
                t=a[i][j];a[i][j]=a[j][i];a[j][i]=t;
            }
        }
    }
}
int main() {
    int max = N>M?N:M;
    
    int a[M][M] = {{1,2,3,4},{5,6,7,8},{9,10,11,12}};
    cout<<"原始数组:\n";
    for(int i = 0; i < N; i++){//打印数组
        for(int j = 0; j < M; j++){
            cout<<a[i][j]<<" ";
        }
        cout<<endl;
    }
    ReverseArray(a);
    cout<<"\n转置后的数组为：\n";
    for(int i = 0; i < M; i++){//转置数组
        for(int j = 0; j < N; j++){
            cout<<a[i][j]<<" ";
        }
        cout<<endl;
    }
    
    return 0;
}