? 此推箱子游戏可以实现人物移动,箱子移动,人物不出框,自义定文件关卡,重新开始以及回退复位等功能的实现,由于系统或版本问题,关卡和人物及物体未做美化处理,希望美化的可自行美化。
1.所用到的宏
#include <stdio.h>
#include <stdlib.h>
#include <getopt.h>
#define MAX_ROWS 16
#define MAX_CLOS 16
#define MAX_LEVEL 5
#define FILE_NAME_LEN 40
#define ROAD 0 //路
#define WALL 1 //墙
#define BOX 2 //箱子
#define TERM 3 //门
#define MOUS 4 //老鼠
#define IGN 224 //无效的键值
#define LEFT 75 //上下左右相对应的键值
#define RIGHT 77
#define UP 72
#define DOWN 80
#define MINT MOUS+TERM //老鼠在门上
#define BINT BOX+TERM //箱子在门上
#define QUIT 'q'//退出
#define RESET 'r'//重新开始
#define BACK 'b'//回退
#define NM 0
#define MM 1
#define BM 2
#define MAX_BACK_STEP 10//回退最多的步数
2.变量声明
struct Act{
int dir;
int sta;
};
struct Act acts[MAX_BACK_STEP] = {};
int stepsize = 0;//用于记录回退的数量
int newindex = -1;//用于记录产生一个新的动作
int board[MAX_ROWS][MAX_CLOS] = {};
int row, col;
int mx = 0,my = 0;//记录老鼠位置
int bcnt = 0;//记录箱子
3.地图文件开启
void load(int level){//将地图文件存放在Dev-CC文件夹下
char fileName[FILE_NAME_LEN] = "";
sprintf(fileName,"%d.txt",level);
FILE *fp = fopen(fileName,"r");//只读形式打开文件
if(fp == NULL){
printf("%s文件打开失败\n",fileName);
exit(-1);//失败退出
}
fscanf(fp,"%d %d",&row,&col);
int i,j;
bcnt = 0;
for(i=0;i<row;i++){
for(j=0;j<col;j++){
fscanf(fp,"%d",&board[i][j]);//读取地图行和列
if(board[i][j] == MOUS || board[i][j] == MINT){
mx = i;
my = j;
}
else if(board[i][j] == BOX || board[i][j] == BINT){
++bcnt;
}
}
}
fclose(fp);
stepsize = 0;
newindex = -1;//返回值初始化
}
4.地图显示及记录模块
//显示地图,记录箱子到达终点
int show(void){
int i,j;
int bs = 0;
for(i=0;i<row;i++){
for(j=0;j<col;j++){
switch(board[i][j]){//画出地图
case ROAD:
printf(" ");
break;
case WALL:
printf("#");
break;
case BINT:
++bs;
case BOX:
printf("@");
break;
case TERM:
printf("O");
break;
case MOUS:
case MINT:
printf("&");
break;
}
}
printf("\n");
}
return bs;
}
5.物体的移动和关卡的延续
int move(int stepx,int stepy){//老鼠和箱子的移动
int nx = mx + stepx;
int ny = my + stepy;
if (board[nx][ny] == ROAD || board[nx][ny] == TERM){
board[mx][my] -= MOUS;
board[nx][ny] += MOUS;
mx = nx;
my = ny;
return MM;
}
else if(board[nx][ny] == BOX || board[nx][ny] == BINT){//推着箱子走
int nnx = nx + stepx;
int nny = ny + stepy;//箱子的坐标
if(board[nnx][nny] == ROAD || board[nnx][nny] == TERM){
board[nnx][nny] += BOX;//箱子到达新的地方
board[nx][ny] -= BOX;//箱子从原来的地方离开
board[mx][my] -= MOUS;//老鼠离开
board[nx][ny] += MOUS;//老鼠到达的新的点
mx = nx;
my = ny;
return BM;
}
}
return NM;
}
6.回退功能的实现(最难部分)
void moveback(int stepx,int stepy){//回退
int nx = mx+stepx;
int ny = my+stepy;
board[mx][my] -= MOUS;
board[nx][ny] += MOUS;
if(acts[newindex].sta == BM){
int bx = mx-stepx;
int by = my-stepy;
board[bx][by] -=BOX;
board[mx][my] +=BOX;
}
mx = nx;
my = ny;
}
void back(void){
if(stepsize >0){
switch(acts[newindex].dir){
case UP:
moveback(+1,0);
break;
case DOWN:
moveback(-1,0);
break;
case LEFT:
moveback(0,+1);
break;
case RIGHT:
moveback(0,-1);
break;
}
--stepsize;
--newindex;
if(newindex == -1){
newindex = MAX_BACK_STEP -1;
}
}
}
7.游戏运行主要部分
void play(int level){
while(1){
system("cls");//清屏
int ret = show();
if(ret == bcnt){//箱子和被推到终点的箱子数一样时
printf("恭喜过关,按任意键进入下一关!!");
getch();
return;
}
int key = getch();
if(key == IGN){
key = getch();
}
if(key == QUIT){//退出
printf("GAME OVER\n");
exit(0);
}
else if(key == RESET){//重新开始
load(level);//重新加载地图
}
else if(key == BACK){//回退功能
back();
}
ret = NM;
switch(key){
case UP:
ret = move(-1,0);
break;
case DOWN:
ret = move(+1,0);
break;
case LEFT:
ret = move(0,-1);
break;
case RIGHT:
ret = move(0,+1);
break;
}
if(ret == MM || ret == BM){//保存有效动作 用于回退
struct Act act = {key,ret}; //记录动作
++newindex;
if(newindex>= MAX_BACK_STEP){
newindex = 0;
}
acts[newindex] = act;
if(stepsize<MAX_BACK_STEP){
++stepsize;//可以退回的步数+1
}
}
}
}
//运行函数
void run(void){
int level;
for(level=1;level<=MAX_LEVEL;level++){
load(level);
play(level);
}
}
//主函数
int main(int argc, char *argv[]) {
run();
return 0;
}
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?8.参考关卡文件(可使用windos记事本以.txt?形式保存,第一列均为空格)
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具体解释存在于代码中。如有不足,请指正!!! ?
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