[C++知识库]C++继承中的同名静态成员的处理

#define _CRT_SECURE_NO_WARNINGS 1
#include <iostream>
using namespace std;
class Base
{
public:
	static int A;
	int B{};
	static void func(){cout << "Base的静态成员函数调用" << endl;}
	static void func(const int& m_A)
	{
		A = m_A;
		cout << "调用Base静态成员函数后A = " << A << endl;
	}
protected:
private:
};
int Base::A = 10;

class Son : public Base
{
public:
	static int A;
	int B{};
	static void func(){cout << "Son的静态成员函数的调用" << endl;}
	static void func(const int& m_A)
	{
		A = m_A;
		cout << "调用Son静态成员函数后A = " << A << endl;
	}
protected:
private:
};
int Son::A = 20;
void test01()
{
	//cout << Base::B << endl; 非静态成员不能通过类名访问
	Son s1;
	cout << s1.A << endl;
	cout << s1.Base::A << endl;  //必须添加作用域才能访问父类中的同名成员变量
}
void test02()
{
	//通过对象访问：
	Son s2;
	s2.func();
	s2.Base::func();
	s2.Base::func(2000);

	//通过类进行访问：
	Son::func(50);
	Son::func();
	Son::Base::func();
	Son::Base::func(500);

}
int main()
{
	test01();
	test02();
	return 0;
}