[C++知识库]【1062】企业奖金问题 （C语言程序设计教程（第三版）课后习题5.8）

switch语句：

#include <stdio.h>
int main()
{
    int x,i,j;

    scanf("%d",&x);
    i=x/100000;
    switch(i)
    {
    case 10:
        printf("%d",j=(x-1000000)*0.01+20000);
        break;
    case 9:
    case 8:
    case 7:
    case 6:
        printf("%d",j=(x-600000)*0.015+20000);
        break;
    case 5:
    case 4:
        printf("%d",j=(x-400000)*0.03+20000);
        break;
    case 3:
    case 2:
        printf("%d",j=(x-200000)*0.05+20000);
        break;
    case 1:
        printf("%d",j=(x-100000)*0.75+10000);
        break;
    default :
        printf("%d",j=x*0.1);
    }
    return 0;
}

if语句：

#include <stdio.h>
#include <stdlib.h>
 
int main()
{
    int I,J;
    scanf("%d",&I);
    if(I<=100000)
        J=I*0.1;
    else if(I<=200000)
        J=100000*0.1+(I-100000)*0.075;
    else if(I<=400000)
        J=100000*0.1+(200000-100000)*0.075+(I-200000)*0.05;
    else if(I<=600000)
        J=100000*0.1+(200000-100000)*0.075+(400000-200000)*0.05+(I-600000)*0.03;
    else if(I<=1000000)
        J=100000*0.1+(200000-100000)*0.075+(400000-200000)*0.05+(600000-400000)*0.03+(I-600000)*0.015;
    else
        J=100000*0.1+(200000-100000)*0.075+(400000-200000)*0.05+(600000-400000)*0.03+(1000000-600000)*0.015+(I-1000000)*0.01;
    printf("%d\n",J);
    return 0;
}