[C++知识库]c++中 lambda函数中调用自身类函数

类函数中得lambda表达式中一般不能调用 自身类得函数

有两种办法可以调用:

1: 将需要调用得函数编程静态函数, 那么可以在lambda中直接调用

2: 将this指针传入进lambda函数

		XZOrdering* ths = this;
		auto checkValue = [&ranges, &remaining, isContained, isOverlapped, ths](XElement & quad, short level)
		{
			ull  min, max;
			if (isContained(quad))
			{
				ths->sequenceInterval(quad.xmin, quad.ymin, level, false, min, max);
				ranges.emplace_back(min, max, true);
			}
			else if (isOverlapped(quad))
			{
				ths->sequenceInterval(quad.xmin, quad.ymin, level, true, min, max);
				ranges.emplace_back(min, max, false);
				auto cds = quad.children();
				for (int i = 0; i < cds.size(); i++)
					remaining.emplace_back(cds[i]);

			}
		};