#include<bits/stdc++.h>
using namespace std;
#define rep(i,l,r) for(int i=(l);i<=(r);i++)
#define per(i,l,r) for(int i=(l);i>=(r);i--)
#define ll long long
#define mset(s,t) memset(s,t,sizeof(t))
#define mcpy(s,t) memcpy(s,t,sizeof(t))
#define fi first
#define se second
#define pb push_back
#define all(x) (x).begin(),(x).end()
#define SZ(x) ((int)(x).size())
#define mp make_pair
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> Vll;
typedef vector<pair<int, int> > vpii;
typedef vector<pair<ll, ll> > vpll;
const ll mod = 1e9 + 7;
//const ll mod = 998244353;
const double pi = acos(-1.0);
inline ll qmi (ll a, ll b) {
ll ans = 1;
while (b) {
if (b & 1) ans = ans * a%mod;
a = a * a %mod;
b >>= 1;
}
return ans;
}
inline int read () {
int x = 0, f = 0;
char ch = getchar();
while (!isdigit(ch)) f |= (ch=='-'),ch= getchar();
while (isdigit(ch)) x = x * 10 + ch - '0', ch = getchar();
return f?-x:x;
}
template<typename T> void print(T x) {
if (x < 0) putchar('-'), x = -x;
if (x >= 10) print(x/10);
putchar(x % 10 + '0');
}
inline ll sub (ll a, ll b) {
return ((a - b ) %mod + mod) %mod;
}
inline ll add (ll a, ll b) {
return (a + b) %mod;
}
inline ll inv (ll a) {
return qmi(a, mod - 2);
}
bool st[10100];
int n, m;
int cnt[10];
vector<int> ans, p;
map<string,int> vis;
void dfs(int u) {
if (u== m) {
string s = "";
for (auto t : ans)
s += to_string(t);
if (vis[s]) return;
vis[s] = 1;
for (auto t : ans) {
cout << t << ' ';
}
puts("");
return;
}
for (int j = 1; j <= n; j ++) {
if (!cnt[j]) continue;
cnt[j] -= 1;
ans.pb(j);
dfs(u + 1);
ans.pop_back();
cnt[j] += 1;
}
}
void solve() {
cin >> n ;
for (int i =1; i <= n; i ++)
{
cin >> cnt[i];
for (int j = 1; j <= cnt[i]; j ++)
p.pb(i);
m += cnt[i];
}
dfs(0);
}
int main () {
// ios::sync_with_stdio(0),cin.tie(0), cout.tie(0);
int t;
t =1;
while (t --) solve();
return 0;
}
直接把所有要用到的数加进来的排法会超时
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