[C++知识库]7-10 数字液晶屏幕---简单题

#include<stdio.h> 
#include<string.h>
using namespace std;

int main()
{
    char a[10][16] = { " - | |   | | - ","     |     |   "," -   | - |   - "," -   | -   | - ","   | | -   |   "," - |   -   | - "," - |   - | | - "," -   |     |   "," - | | - | | - "," - | | -   | - " };
    //a储存的是每个数字字形图横着变过来 
	//a[0]储存0的字形图 
//	 - 
//	| |
//	| | 
//	 - 
//	0竖着是这个样子，横向存到a里边变成  - | |   | | - 
	

	char p[20];
    scanf("%s",p);
    //p是输入的数字串 
    int p_size=strlen(p);
    int  m = 0;
    for (int k = 0; k < 5; k++) {
        for (int j = 0; j < p_size; j++) {
            int n = p[j] - '0';
            //n是当前这个数字 
            for (int i=0; i < 3; i++) {
            	//每次输出一行，即每个数字的上边3个字符
				//因为横着放到字符串里边了 ，这个m就对应偏移位置，n是数字位置 
                printf("%c",a[n][i+m]);
            }
        }
        printf("\n");
        
        //这一行数字输出完了，字符串偏移位置+3变为下一行 
        m = m + 3;
    }
}