归并排序
- 利用分治和递归的思想,先分,后并
java代码
public class Tset {
public static void main(String[] args) {
int[] arr = new int[]{4,6,7,1,2,8,5};
mergeSort(arr);
for (int i = 0; i < arr.length; i++) {
System.out.println(arr[i]);
}
}
private static void mergeSort(int[] arr){
mergeSortInertal(arr,0,arr.length-1);
}
private static void mergeSortInertal(int[] arr,int low,int high){
if (low >= high) return;
int mid = (low+high)>>>1;
mergeSortInertal(arr,low,mid);
mergeSortInertal(arr,mid+1,high);
merge(arr,low,mid,high);
}
private static void merge(int[] arr,int low,int mid,int high){
int s1 = low;
int s2 = mid+1;
int [] ret = new int[high-low+1];
int i = 0;
while (s1 <= mid && s2 <= high){
if (arr[s1] < arr[s2]){
ret[i++] = arr[s1++];
}else{
ret[i++] = arr[s2++];
}
}
while (s1 <=mid){
ret[i++] = arr[s1++];
}
while (s2 <= high){
ret[i++] = arr[s2++];
}
for (int j = 0; j < ret.length; j++) {
arr[low+j] = ret[j];
}
}
}
链表归并排序
public static ListNode sortList(ListNode head) {
ListNode cur = head;
while(cur.next != null && cur != null){
cur = cur.next;
}
return sortList(head,cur);
}
public static ListNode sortList(ListNode head,ListNode end) {
if(head == null ) return head;
if (head.next == end){
head.next = null;
return head;
}
ListNode low = head,fast = head;
while(fast != end){
low = low.next;
fast = fast.next;
if(fast != end){
fast = fast.next;
}
}
ListNode mid = low;
ListNode m1 = sortList(head,mid);
ListNode m2 = sortList(mid,end);
return merge(m1,m2);
}
private static ListNode merge(ListNode m1,ListNode m2){
ListNode newTmp = new ListNode(0);
ListNode tmp1 = m1;
ListNode tmp2 = m2;
ListNode tmp = newTmp;
while(tmp1 != null && tmp2 != null){
if(tmp1.val < tmp2.val ){
tmp.next = tmp1;
tmp1 = tmp1.next;
}else{
tmp.next = tmp2;
tmp2 = tmp2.next;
}
tmp = tmp.next;
}
if(tmp1 != null){
tmp.next = tmp1;
}else if(tmp2 != null){
tmp.next = tmp2;
}
return newTmp.next;
}
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