java使用stream实现list中对象属性的合并: 根据两个List中的某个相同字段合并成一条List,包含两个List中的字段
一、前言
为什么要用Lambda表达式 和Stream流 做集合的处理? 因为效率高、代码简洁、高端大气上档次!
(1)描述:比如一个List集合中List<对象1>,该对象1包含A、B和C列;另外一个List集合中List<对象2>,该对象2包含A、D列;
(2)问题:需要将两个List合成List<对象3>返回,该对象3包含A、B、C、D列
(3)实现:使用stream实现两个list集合合并成一个list集合
简要说明:filter的使用方式为: filter(item -> item的逻辑判断 ) ,其中filter会保留判断条件为true的记录
二、示例
示例1:java8 合并两个 list<map>
java8 合并两个 list<map>, 并将userId 相同的所有属性合并到一个map中
list1中对象的属性:userId、userName list2中对象的属性:userId、gender、age 最总集合中对象的属性:userId、userName、gender、age
import java.util.*;
import java.util.stream.Collectors;
public class ListTest {
public static void main(String[] args) {
mergeList();
}
public static List<Map<String,Object>> mergeList(){
List<Map<String,Object>> list1 = new ArrayList<>();
Map<String,Object> data=new HashMap<>();
data.put("userId","100001");
data.put("userName","唐僧");
list1.add(data);
data=new HashMap<>();
data.put("userId","100002");
data.put("userName","八戒");
list1.add(data);
data=new HashMap<>();
data.put("userId","100003");
data.put("userName","悟空");
list1.add(data);
data=new HashMap<>();
data.put("userId","100004");
data.put("userName","沙僧");
list1.add(data);
List<Map<String,Object>> list2 = new ArrayList<>();
data=new HashMap<>();
data.put("userId","100001");
data.put("gender","男");
data.put("age",20);
list2.add(data);
data=new HashMap<>();
data.put("userId","100002");
data.put("gender","雄");
data.put("age",1000);
list2.add(data);
data=new HashMap<>();
data.put("userId","100003");
data.put("gender","雄");
data.put("age",600);
list2.add(data);
data=new HashMap<>();
data.put("userId","100004");
data.put("gender","男");
data.put("age",800);
list2.add(data);
List<Map<String, Object>> list = list1.stream().map(m -> {
list2.stream().filter(m2-> Objects.equals(m.get("userId"),m2.get("userId"))).forEach(m2-> {
m.put("gender",m2.get("gender"));
m.put("age",m2.get("age"));
});
return m;
}).collect(Collectors.toList());
for(Map<String, Object> map:list){
System.out.println(map.toString());
}
return list;
}
}
合并运行结果:
示例2:java8 合并两个 list<T>
java8 合并两个 list<T>, 并将tickeId相同的所有属性合并到一个T中
list1中对象的属性:ticketId、ticketName list2中对象的属性:ticketId、saleNum、batchAvailableNum 最总集合中对象的属性:ticketId、ticketName、saleNum、batchAvailableNum
import java.util.*;
import java.util.stream.Collectors;
public class ListTest1 {
public static void main(String[] args) {
mergeList();
}
public static List<Ticket> mergeList(){
List<Ticket> list1 = new ArrayList<>();
Ticket data=new Ticket();
data.setTicketId("100001");
data.setTicketName("唐僧");
list1.add(data);
data=new Ticket();
data.setTicketId("100002");
data.setTicketName("八戒");
list1.add(data);
data=new Ticket();
data.setTicketId("100003");
data.setTicketName("悟空");
list1.add(data);
data=new Ticket();
data.setTicketId("100004");
data.setTicketName("沙僧");
list1.add(data);
List<Ticket> list2 = new ArrayList<>();
data=new Ticket();
data.setTicketId("100001");
data.setSaleNum("20");
data.setBatchAvailableNum("10");
list2.add(data);
data=new Ticket();
data.setTicketId("100001");
data.setSaleNum("20");
data.setBatchAvailableNum("10");
list2.add(data);
data=new Ticket();
data.setTicketId("100002");
data.setSaleNum("1000");
data.setBatchAvailableNum("600");
list2.add(data);
data=new Ticket();
data.setTicketId("100003");
data.setSaleNum("600");
data.setBatchAvailableNum("100");
list2.add(data);
data=new Ticket();
data.setTicketId("100004");
data.setSaleNum("800");
data.setBatchAvailableNum("300");
list2.add(data);
List<Ticket> list = list1.stream().map(m -> {
list2.stream().filter(m2-> Objects.equals(m.getTicketId(),m2.getTicketId())).forEach(m2-> {
m.setSaleNum(m2.getSaleNum());
m.setBatchAvailableNum(m2.getBatchAvailableNum());
});
return m;
}).collect(Collectors.toList());
for(Ticket ticket:list){
System.out.println(ticket.getTicketId()+","+ticket.getTicketName()+","+ticket.getSaleNum()+","+ticket.getBatchAvailableNum());
}
return list;
}
}
合并运行结果:
示例3:java8 合并两个 list<T>,集合个数前者小于后者,要后者
list1中对象的属性:ticketId、ticketName list2中对象的属性:ticketId、batchId 最总集合中对象的属性:ticketId、ticketName、batchId list1: ticketId:10001 , ticketName:唐僧 ticketId:10002 , ticketName:八戒 list2: ticketId:10001 , batchId:1 ticketId:10001 , batchId:2 ticketId:10002 , batchId:1 ticketId:10002 , batchId:2 ticketId:10003 , batchId:2 想要的结果:list1合并到 list 2 ticketId:10001 , ticketName:唐僧,batchId:1 ticketId:10001 , ticketName:唐僧,batchId:2 ticketId:10002 , ticketName:八戒,batchId:1 ticketId:10002 , ticketName:八戒,batchId:2 ticketId:10003 , ticketName:八戒,batchId:2
代码实现:
import java.util.ArrayList;
import java.util.List;
import java.util.Objects;
import java.util.stream.Collectors;
public class ListTest2 {
public static void main(String[] args) {
mergeList();
}
public static List<Ticket> mergeList(){
List<Ticket> list1 = new ArrayList<>();
Ticket data=new Ticket();
data.setTicketId("100001");
data.setTicketName("唐僧");
list1.add(data);
data=new Ticket();
data.setTicketId("100002");
data.setTicketName("八戒");
list1.add(data);
List<Ticket> list2 = new ArrayList<>();
data=new Ticket();
data.setTicketId("100001");
data.setBatchId("1");
list2.add(data);
data=new Ticket();
data.setTicketId("100001");
data.setBatchId("2");
list2.add(data);
data=new Ticket();
data.setTicketId("100002");
data.setBatchId("1");
list2.add(data);
data=new Ticket();
data.setTicketId("100002");
data.setBatchId("2");
list2.add(data);
data=new Ticket();
data.setTicketId("100002");
data.setBatchId("3");
list2.add(data);
List<Ticket> list = list2.stream().map(m -> {
list1.stream().filter(m2-> Objects.equals(m.getTicketId(),m2.getTicketId())).forEach(m2-> {
m.setTicketId(m2.getTicketId());
m.setTicketName(m2.getTicketName());
});
return m;
}).collect(Collectors.toList());
for(Ticket ticket:list){
System.out.println(ticket.getTicketId()+","+ticket.getTicketName()+","+ticket.getBatchId());
}
return list;
}
}
合并运行结果:
示例4:java8 合并两个 list<T>,集合个数前者大于后者,要后者
list1中对象的属性:ticketId、ticketName list2中对象的属性:ticketId、batchId 最总集合中对象的属性:ticketId、ticketName、batchId list1: ticketId:10001 , ticketName:唐僧 ticketId:10002 , ticketName:八戒 list2: ticketId:10001 , batchId:1 ticketId:10001 , batchId:2
想要的结果:list1合并到 list 2,过滤掉batch不存在的数据 ticketId:10001 , ticketName:唐僧,batchId:1 ticketId:10001 , ticketName:唐僧,batchId:2
代码实现:
import java.util.ArrayList;
import java.util.List;
import java.util.Objects;
import java.util.stream.Collectors;
public class ListTest3 {
public static void main(String[] args) {
mergeList();
}
public static List<Ticket> mergeList(){
List<Ticket> list1 = new ArrayList<>();
Ticket data=new Ticket();
data.setTicketId("100001");
data.setTicketName("唐僧");
list1.add(data);
data=new Ticket();
data.setTicketId("100002");
data.setTicketName("八戒");
list1.add(data);
List<Ticket> list2 = new ArrayList<>();
data=new Ticket();
data.setTicketId("100001");
data.setBatchId("1");
list2.add(data);
data=new Ticket();
data.setTicketId("100001");
data.setBatchId("2");
list2.add(data);
List<Ticket> list = list2.stream().map(m -> {
list1.stream().filter(m2-> Objects.equals(m.getTicketId(),m2.getTicketId())).forEach(m2-> {
m.setTicketId(m2.getTicketId());
m.setTicketName(m2.getTicketName());
});
return m;
}).collect(Collectors.toList());
for(Ticket ticket:list){
System.out.println(ticket.getTicketId()+","+ticket.getTicketName()+","+ticket.getBatchId());
}
return list;
}
}
合并运行结果:
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