[JavaScript知识库]重写路由push方法

解决相同路由跳转时，报错

const routerPush = Router.prototype.push
Router.prototype.push = function push(location) {
  if(typeof(location)=="string"){
    var Separator = "&";
    if(location.indexOf('?')==-1) { Separator='?'; }
    location = location + Separator + "random=" + Math.random();
  }
  return routerPush.call(this, location).catch(error=> error)
}