[JavaScript知识库]path.resolve()与path.join()对比

当前目录为D:\node，以下为对比测试：

const path = require("path");

console.log(path.resolve("a")); //D:\node\a
console.log(path.join("a")); // a

console.log(path.resolve("/a")); //D:\a
console.log(path.join("/a")); //\a

console.log(path.resolve("/a",'b')); //D:\a\b
console.log(path.resolve("/a",'/b')); //D:\b
console.log(path.join("/a",'b')); //\a\b
console.log(path.join("/a",'/b')); //\a\b

console.log(path.resolve('a','b','/c','d')); //D:\c\d
console.log(path.resolve("a", "b", "/c", "/d")); //D:\d
console.log(path.resolve('a','..','b')) //D:\node\b
console.log(path.join('a','b','/c','d')); //a\b\c\d
console.log(path.join("a", "b", "/c", "/d")); //a\b\c\d
console.log(path.join('a','..','b')) //n

总结，path.resolve()会把/当做根目录，且以最后一个/为根目录。

//前面写了再多的a，b，/c都没有用，以最后一个`/`为准，即/d
console.log(path.resolve("a", "b", "/c", "/d")); //D:\d