当typescript编写代码时出现这个报错怎么办?
例如如下代码及声明
interface IJobData {
generation?: {id: number; name: string; code: string;}[]
publishing?: {id: number; name: string; code:string;}[]
}
const method = ['generation', 'publishing']
const originJobData = {
generation: [
{id: 1, name: 'generation', code: 'test1'},
{id: 2, name: 'test2', code: 'test2' }
],
publishing: [
{id: 3, name: 'publish', code: 'test3'},
{id: 4, name: 'publish11', code: 'test4'},
]
}
const formatJobData: IJobData = {}
method.forEach((method:string)=>{
if (originJobData[method]) formatJobData[method] = originJobData[method]
})
// 此时会报如下错误
Element implicitly has an 'any' type because expression of type 'string' can't be used to index type 'IJobData'.
No index signature with a parameter of type 'string' was found on type 'IJobData'
又比如:
const str = 'name' as string;
const obj = {
name: 'James Doe',
country: 'Chile',
};
// ?? Error: Element implicitly has an 'any' type
// because expression of type 'string' can't be used
// to index type '{ name: string; }'.
// No index signature with a parameter of type 'string'
// was found on type '{ name: string; }'.ts(7053)
obj[str];
当我们尝试通过对象的属性访问对象的value时,就会报这个错误;遇到这种问题我们如何解决呢?
第一个解决方案:
const str = 'name' as string;
const obj = {
name: 'James Doe',
country: 'Chile',
};
// 👇? "James Doe"
console.log(obj[str as keyof typeof obj]);
// 👇? type T = "name" | "country"
type T = keyof typeof obj;
第二种解决方案:
const str = 'name' as string;
interface Person {
name: string;
country: string;
}
const obj: Person = {
name: 'James Doe',
country: 'Chile',
};
console.log(obj[str as keyof Person]); // 👉? "James Doe"
// 👇? type T = "name" | "country"
type T = keyof Person;
第三种解决方案
interface Person {
name: string;
country: string;
}
// 👇? this will only ever be one of object's keys
const str: keyof Person = 'name';
const obj: Person = {
name: 'James Doe',
country: 'Chile',
};
console.log(obj[str]); // 👉? "James Doe"
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