方法一：
let names = [1,3,3];
let length = names.length / 2
let nameNum = names.reduce((pre,cur)=>{
? if(cur in pre){
? ? pre[cur]++
? }else{
? ? pre[cur] = 1
? }
? return pre
},{})
console.log(nameNum)
let obj = Object.entries(nameNum)
console.log(obj)
let add = obj.filter((item) => {
? ? return item[1]>length
})
let kkk = add[0] || 0
let ooo = add.length>0 ? kkk[0]:0
console.log(ooo)
方法二：
let names = [1,3,3];
let out = 0
let length = names.length / 2
let nameNum = names.reduce((pre,cur)=>{
? if(cur in pre){
? ? pre[cur]++
? }else{
? ? pre[cur] = 1
? }
? return pre
},{})
console.log(nameNum)
for(let [key,value] of Object.entries(nameNum)) {
? ? if(value > length){
? ? ? ? out = value
? ? }
}
console.log(out)
