[Python知识库]bugku misc-多彩

下载图片

用隐写工具发现

分析一下发现pk头Sava bin 另存为zip文件，用7z解压（其他的会报错），发现要密码
就上网找了下wp。。发现密码竟然是YSL对应口红色号的二进制转字符
ps取颜色，然后就去找YSL的口红色号

php脚本
<?php
        $data='';
        $ch = curl_init();
            curl_setopt($ch, CURLOPT_URL,'https://www.yslbeautyus.com/on/demandware.store/Sites-ysl-us-Site/en_US/Product-Variation?pid=194YSL'); //地址
            curl_setopt($ch, CURLOPT_POST, 1);
            curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
            //curl_setopt($ch, CURLOPT_HTTPHEADER,$data);
            curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
            curl_setopt($ch, CURLOPT_HEADER, 0);
            curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows; U; Windows NT 5.1; zh-CN; rv:1.9.1.5) Gecko/20091102 Firefox/3.5.5');
            curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1);
            $rr=curl_exec($ch);
            curl_close($ch);
            $pat='/style="background-color: #(.*?)" title="(.*?)">/';
            preg_match_all($pat,$rr,$dd);
            $color=array_flip($dd[1]);
            $num=$dd[2];
            //print_r($num);die;
            $arr=array('BC0B28','D04179','D47A6F','C2696F','EB8262', 'CF1A77','C0083E','BC0B28','BC0B28','D13274', '6A1319','BC0B28','BC0B28','D4121D','D75B59', 'DD8885','CE0A4A','D4121D','7E453A','D75B59', 'DD8885');  //这里是用ps取到的颜色代码
            foreach ($arr as $k => $v) {
                  if(in_array($v,$color))
                  {
                        print_r($num[$color[$v]]);
                        echo "<br />";
                  }
 
            }

python,这里如果要用python脚本的话，需要下载模块
地址：https://github.com/warnerjon12/libnum

在当前目录下安装，python setup.py install
也可参考：https://www.cnblogs.com/pcat/p/7225782.html

# -*- coding:utf8 -*-
__author__='pcat@chamd5.org'
import requestsimport re
import libnum

def foo(): 
url=r'https://www.yslbeautyus.com/on/demandware.store/Sites-ysl-us-Site/en_US/Product-Variation?pid=194YSL' 
cont=requests.get(url).content 
# print cont 
pattern=r'YSL_color=(.*?)%20[sS]*?background-color: #(.*?)"' 
rst=re.findall(pattern,cont) 
dYSL={} 
for num,color in rst:  
dYSL[color]=int(num.lstrip('0')) 
lst=['BC0B28','D04179','D47A6F','C2696F','EB8262', 'CF1A77','C0083E','BC0B28','BC0B28','D13274', '6A1319','BC0B28','BC0B28','D4121D','D75B59', 'DD8885','CE0A4A','D4121D','7E453A','D75B59', 'DD8885'] 
flag=''.join('{:b}'.format(dYSL[i]) for i in lst) 
print libnum.b2s(flag) 
pass

if __name__ == '__main__': 
foo() 
print 'ok'

用python就不需要转了，php的话需要色号转二进制

现在就可以将这些色号编码转为二进制。。然后再转为字符串。。

这里就需要用python了。。(因为这个转换不难。。刚好会)

    # -*- coding:utf8 -*-
    import sys
    import libnum
     
    ss=''
    s=[1,27,59,11,23,7,57,1,1,76,222,1,1,50,214,6,77,50,53,214,6]
    for i in s:
    	ss+=bin(i)[2:]
    print ss
    type = sys.getfilesystemencoding()
     
    print libnum.b2s(ss).decode('utf-8').encode(type)

输出后为白学家，密码就是这个

解压即可得到flag

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