#include<stdio.h>
#include<string.h>
#include<stdlib.h>
int main()
{
int n, ji;
scanf("%d %d", &n, &ji);
char arr[1000];
n = n + 1;
//在这里之所以要n+1是因为下面的gets函数会先将/n给输入字符串,所以此行作废
int zhen = 0;
while (n != 0)
{
n--;
gets(arr);
int a = strlen(arr);
int flag = 0;
//a记录字符串长度,flag记录是否出现了easy或者qiandao
for (int i = 0; i <= a - 4; i++)
{
if (arr[i] == 'e' && arr[i + 1] == 'a' && arr[i + 2] == 's' && arr[i + 3] == 'y')
{
flag = 1;
break;
}
}
for (int i = 0; i <= a - 7; i++)
{
if (arr[i] == 'q' && arr[i + 1] == 'i' && arr[i + 2] == 'a' && arr[i + 3] == 'n' && arr[i + 4] == 'd' && arr[i + 5] == 'a' && arr[i + 6] == 'o')
{
flag = 1;
break;
}
}
//用以上两个循环来排查easy和qiandao,如果a小于4,则根本无法进入循环
if (flag == 0&&a!=0)
{
zhen++;
}
if (ji == zhen - 1)
{
printf("%s", arr);
break;
}
}
if (ji >= zhen)
{
printf("Wo AK le");
}
return 0;
}
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