[人工智能]近端梯度下降法 (proximal gradient descent)算法python实现完整版

上一节次梯度python实现介绍了python求解次梯度的基本算法，但针对的是无偏置项的求解：

本节我们增加偏置项，推导完整的proximal gradient descent算法的python实现代码，最优化目标函数变为：

目标是预估权重和偏置项,那么权重项的次微分为：

而偏置项的次微分为：

其中，为的元素数，通常是一次梯度算法的样本数，那么基于上节的代码，我们给出完整的proximal gradient descent算法的python实现：

# -*- coding: utf-8 -*-
import numpy as np
import scipy as spy
from scipy.sparse import csc_matrix
import matplotlib.pyplot as plt
import time   #用来计算运行时间
#=======模拟数据======================
m = 512
n = 1024
#稀疏矩阵的产生，A使用的是正态稀疏矩阵
u= spy.sparse.rand(n,1,density=0.1,format='csc',dtype=None)
u1 = u.nonzero()
row = u1[0]
col = u1[1]
data = np.random.randn(int(0.1*n))
u = csc_matrix((data, (row, col)), shape=(n,1)).toarray() #1024 * 1
a = np.random.randn(m,n) # 512 * 1024
bias = 2.632 # 偏置
y0 = np.dot(a,u) + bias # a * u + bias, 512 * 1
v = 1e-3      #v为题目里面的miu
def f(x0):    #目标函数 1/2*||Ax + b - y0||^2 + mu*||x||1
    return 1/2*np.dot((np.dot(a,x0) + bias -y0).T,np.dot(a,x0) + bias -y0)+v*sum(abs(x0))
def S(x1,v):
    for i in range(len(x1)):
        if np.abs(x1[i]) - v > 0:
            x1[i] = np.sign(x1[i]) * (np.abs(x1[i]) - v)
        else:
            x1[i] = 0
    return x1
#==========初始值=============================
#x0 = np.zeros((n,1)) #1024 * 1
x0 = (2.0*np.random.random((n,1)) - 1.0) * 0.01
b0 = np.random.random(1)
y = []
time1 = []
start = time.clock()
print("begin to train!")
oneVecs = np.ones((m,1))
#=========开始迭代==========================
for i in range(3000):
    if i %10 == 0:
        if len(y) > 0:
            print("step " + str(i) + "val: " + str(y[len(y) - 1]))
    mid_result = f(x0) 
    y.append(f(x0)[0,0])    #存放每次的迭代函数值   
    #g0 = (np.dot(np.dot(a.T,a),x0)-np.dot(a.T,b) + v*np.sign(x0)) 
    #次梯度x: A^T(Ax + 1 * b - y0) + mu * sign(x)
    #剃度b: b * 1^T * (Ax - y) + b * m
    g0 = np.dot(np.dot(a.T,a),x0) + np.dot(a.T,oneVecs)*b0 -np.dot(a.T,y0)
    gb0 = (np.dot(oneVecs.T, np.dot(a, x0)) - np.dot(oneVecs.T,y0) + m * b0)
    
    t = 0.025/np.sqrt(sum(np.dot(g0.T,g0)))    #设为0.01效果比0.1好很多，步长
    
    x1 = S(x0 - t[0]*g0, v)
    b1 = b0 - t[0]*gb0
    x0 = x1
    b0 = b1    
    end = time.clock()
    time1.append(end)
y = np.array(y).reshape((3000,1))    
time1 = np.array(time1)
time1 = time1 - start
time2 = time1[np.where(y - y[999] < 10e-4)[0][0]]
plt.plot(y)
plt.show()
for val in y:
    print(val)