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   -> 大数据 -> Mysql子查询 -> 正文阅读

[大数据]Mysql子查询

目录

1、子查询的基本使用及分类

1.1、子查询的基本使用

1.2、子查询的分类

2、单行子查询

2.1、单行子查询比较操作符

?2.2、代码示例

2.3、HAVING中的子查询

2.4、CASE中的子查询

2.5、子查询中的空值问题

3、多行子查询

3.1、多行比较操作符

3.2、代码示例?

4、相关子查询

4.1、相关子查询执行过程

4.2、代码示例

4.3、EXISTS 与 NOT EXISTS关键字

4.4、相关更新

4.5、相关删除

5、关于自连接和子查询效率问题

6、练习


子查询指一个查询语句嵌套在另一个查询语句内部的查询,这个特性从MySQL 4.1开始引入。

SQL 中子查询的使用大大增强了 SELECT 查询的能力,因为很多时候查询需要从结果集中获取数据,或者需要从同一个表中先计算得出一个数据结果,然后与这个数据结果(可能是某个标量,也可能是某个集合)进行比较。

1、子查询的基本使用及分类

1.1、子查询的基本使用

  • 子查询的基本语法结构:括号内为内查询(子查询),括号外为外查询(主查询)

  • 在SELECT中,除了GROUP BY 和 LIMIT之外,其他位置都可以声明子查询

  • 子查询(内查询)在主查询之前一次执行完成。

  • 子查询的结果被主查询(外查询)使用 。

  • 注意事项

    • 子查询要包含在括号内

    • 将子查询放在比较条件的右侧

    • 单行操作符对应单行子查询,多行操作符对应多行子查询

1.2、子查询的分类

1、按内查询的结果返回一条还是多条记录,将子查询分为单行子查询多行子查询

2、按内查询是否被执行多次,将子查询划分为相关(或关联)子查询不相关(或非关联)子查询

????????子查询从数据表中查询了数据结果,如果这个数据结果只执行一次,然后这个数据结果作为主查询的条件进行执行,那么这样的子查询叫做不 ????????相关子查询。

????????同样,如果子查询需要执行多次,即采用循环的方式,先从外部查询开始,每次都传入子查询进行查询,然后再将结果反馈给外部,这种嵌套 ????????的执行方式就称为相关子查询。

2、单行子查询

2.1、单行子查询比较操作符

?2.2、代码示例

#题目:查询工资大于149号员工工资的员工的信息
SELECT employee_id, last_name, salary
FROM employees
WHERE salary > (
		SELECT salary
		FROM employees
		WHERE employee_id = 149
		);

#题目:返回job_id与141号员工相同,salary比143号员工多的员工姓名,job_id和工资
SELECT last_name, job_id, salary
FROM employees
WHERE job_id = (
		SELECT job_id
		FROM employees
		WHERE employee_id = 141
		)
AND salary > (
	      SELECT salary
	      FROM employees
	      WHERE employee_id = 143
	      );


#题目:返回公司工资最少的员工的last_name,job_id和salary
SELECT last_name, job_id, salary
FROM employees
WHERE salary = (
		SELECT MIN(salary)
		FROM employees
		);


#题目:查询与141号员工的manager_id和department_id相同的其他员工的employee_id,manager_id,department_id。
#方式1:
SELECT employee_id, manager_id, department_id
FROM employees
WHERE manager_id = (
		SELECT manager_id
		FROM employees
		WHERE employee_id = 141
		)
AND department_id = (
		SELECT department_id
		FROM employees
		WHERE employee_id = 141
		)
AND employee_id <> 141;
#方式2:了解
SELECT employee_id,manager_id,department_id
FROM employees
WHERE (manager_id,department_id) = (
				    SELECT manager_id,department_id
			            FROM employees
				    WHERE employee_id = 141
				   )
AND employee_id <> 141;

2.3、HAVING中的子查询

  • 首先执行子查询。

  • 向主查询中的HAVING 子句返回结果

#题目:查询最低工资大于110号部门最低工资的部门id和其最低工资
SELECT department_id, MIN(salary)
FROM employees
WHERE department_id IS NOT NULL
GROUP BY department_id
HAVING MIN(salary) > (
			SELECT MIN(salary)
			FROM employees
			WHERE department_id = 110
			);

2.4、CASE中的子查询

SELECT employee_id,last_name,CASE department_id WHEN(SELECT department_id
						     FROM departments
						     WHERE location_id = 1800) THEN 'Canada'
						     ELSE 'USA' END "location"
FROM employees

2.5、子查询中的空值问题

子查询不返回任何行,主查询也不返回任何行

SELECT last_name, job_id
FROM   employees
WHERE  job_id =
                 #子查询中空值
                (SELECT job_id
                 FROM   employees
                 WHERE  last_name = 'Haas');

3、多行子查询

  • 也称为集合比较子查询

  • 内查询返回多行

  • 使用多行比较操作符

3.1、多行比较操作符

3.2、代码示例?

1、IN

SELECT employee_id, last_name
FROM   employees
WHERE  salary IN
                (SELECT   MIN(salary)
                 FROM     employees
                 GROUP BY department_id); 

2、ANY

#题目:返回其它job_id中比job_id为‘IT_PROG’部门任一工资低的员工的员工号、姓名、job_id 以及salary
SELECT employee_id, last_name, job_id, salary
FROM employees
WHERE job_id <> 'IT_PROG'
AND salary < ANY(
		SELECT salary
		FROM employees
		WHERE job_id = 'IT_PROG'
		);

3、ALL

#题目:查询平均工资最低的部门id
#MySQL中聚合函数是不能嵌套使用的。
#方式1:
SELECT department_id
FROM employees
GROUP BY `department_id`
HAVING AVG(salary) = (
			SELECT MIN(avg_sal)
			FROM (
				SELECT AVG(salary) avg_sal
				FROM employees
				GROUP BY department_id
				) t_dept_avg_sal
		      );
#方式2:
SELECT department_id
FROM employees
GROUP BY `department_id`
HAVING AVG(salary) <= ALL(
		SELECT AVG(salary)
		FROM employees
		GROUP BY department_id
		)

4、相关子查询

4.1、相关子查询执行过程

如果子查询的执行依赖于外部查询,通常情况下都是因为子查询中的表用到了外部的表,并进行了条件关联,因此每执行一次外部查询,子查询都要重新计算一次,这样的子查询就称之为关联子查询

相关子查询按照一行接一行的顺序执行,主查询的每一行都执行一次子查询。

说明:子查询中使用主查询中的列 ?

4.2、代码示例

#题目:查询员工中工资大于本部门平均工资的员工的last_name,salary和其department_id
#方式1:使用相关子查询
SELECT last_name, salary, department_id
FROM employees e1
WHERE salary > (
	SELECT AVG(salary)
	FROM employees e2
	WHERE department_id = e1.department_id
	);
#方式2:在FROM中声明子查询
SELECT e1.last_name, e1.salary, e1.department_id
FROM employees e1, (
		SELECT department_id, AVG(salary) avg_sal
		FROM employees e2
		GROUP BY `department_id`
		) e2
WHERE e1.department_id = e2.department_id
AND e1.salary > avg_sal
#题目:查询员工的id,salary,按照department_name 排序
SELECT employee_id, salary
FROM `employees` e
ORDER BY (
	SELECT `department_name`
	FROM `departments` d
	WHERE e.department_id = d.department_id
	);
#题目:若employees表中employee_id与job_history表中employee_id相同的数目不小于2,
#输出这些相同id的员工的employee_id,last_name和其job_id
SELECT e.employee_id, e.last_name, e.job_id
FROM employees e
WHERE 2 <= (
	SELECT COUNT(*)
	FROM `job_history` j
	WHERE j.employee_id = e.employee_id
	);

4.3、EXISTS 与 NOT EXISTS关键字

  • 关联子查询通常也会和 EXISTS操作符一起来使用,用来检查在子查询中是否存在满足条件的行。

  • 如果在子查询中不存在满足条件的行:

    • 条件返回 FALSE

    • 继续在子查询中查找

  • 如果在子查询中存在满足条件的行:

    • 不在子查询中继续查找

    • 条件返回 TRUE

  • NOT EXISTS关键字表示如果不存在某种条件,则返回TRUE,否则返回FALSE。

1、EXISTS

#题目:查询公司管理者的employee_id,last_name,job_id,department_id信息
#方式1:自连接
SELECT DISTINCT m.employee_id, m.last_name, m.job_id, m.department_id
FROM employees e JOIN employees m
ON e.manager_id = m.employee_id;
#方式2:子查询
SELECT e.employee_id, e.last_name, e.job_id, e.department_id
FROM employees e
WHERE e.`employee_id` IN(
		SELECT DISTINCT m.manager_id
		FROM employees m
		);
#方式3:使用EXISTS
SELECT e.employee_id, e.last_name, e.job_id, e.department_id
FROM employees e
WHERE EXISTS (
	SELECT *
	FROM employees m
	WHERE e.`employee_id` = m.manager_id
	);

2、NOT EXISTS

#题目:查询departments表中,不存在于employees表中的部门的department_id和department_name
#方式1
SELECT d.department_id, d.department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id = d.department_id
WHERE e.department_id IS NULL;
#方式2
SELECT department_id, department_name
FROM departments d
WHERE NOT EXISTS (
		SELECT *
		FROM employees e
		WHERE e.department_id = d.department_id
		)

4.4、相关更新

使用相关子查询依据一个表中的数据更新另一个表的数据。

#题目:在employees中增加一个department_name字段,数据为员工对应的部门名称
# 第一步
ALTER TABLE employees
ADD(department_name VARCHAR2(14));
# 第二步
UPDATE employees e
SET department_name =  (SELECT department_name 
	                       FROM   departments d
	                       WHERE  e.department_id = d.department_id);

4.5、相关删除

使用相关子查询依据一个表中的数据删除另一个表的数据。

#删除表employees中,其与emp_history表皆有的数据
DELETE FROM employees e
WHERE employee_id IN  
           (SELECT employee_id
            FROM   emp_history 
            WHERE  employee_id = e.employee_id);

5、关于自连接和子查询效率问题

题目中可以使用子查询,也可以使用自连接。一般情况建议你使用自连接,因为在许多 DBMS 的处理过程中,对于自连接的处理速度要比子查询快得多。

可以这样理解:子查询实际上是通过未知表进行查询后的条件判断,而自连接是通过已知的自身数据表进行条件判断,因此在大部分 DBMS 中都对自连接处理进行了优化。

6、练习

#1.查询和Zlotkey相同部门的员工姓名和工资 
SELECT last_name, salary
FROM employees
WHERE department_id  (
		SELECT department_id
		FROM employees
		WHERE last_name = 'Zlotkey'
		);

#2.查询工资比公司平均工资高的员工的员工号,姓名和工资。 
SELECT employee_id, last_name, salary
FROM employees
WHERE salary > (
		SELECT AVG(salary)
		FROM employees
		);

#3.选择工资大于所有JOB_ID = 'SA_MAN'的员工的工资的员工的last_name, job_id, salary 
SELECT last_name , job_id, salary
FROM employees
WHERE salary > ALL(
		SELECT salary
		FROM employees
		WHERE job_id = 'SA_MAN'
		);

#4.查询和姓名中包含字母u的员工在相同部门的员工的员工号和姓名 
SELECT employee_id, last_name
FROM employees
WHERE department_id IN(
		SELECT DISTINCT department_id
		FROM employees
		WHERE last_name LIKE '%u%'
		);


#5.查询在部门的location_id为1700的部门工作的员工的员工号 
SELECT employee_id
FROM employees
WHERE department_id IN(
		SELECT department_id
		FROM `departments`
		WHERE `location_id` = 1700
		);

#6.查询管理者是King的员工姓名和工资
#方法1
SELECT last_name, salary
FROM employees
WHERE manager_id IN(
		SELECT employee_id
		FROM employees
		WHERE last_name = 'King'
		);

#7.查询工资最低的员工信息: last_name, salary 
SELECT last_name, salary
FROM employees
WHERE salary = (
		SELECT MIN(salary)
		FROM employees
		);

#8.查询平均工资最低的部门信息
#方式1
SELECT *
FROM departments
WHERE department_id = (
		SELECT department_id
		FROM employees
		GROUP BY department_id
		HAVING AVG(salary) = (
					SELECT MIN(avg_sal)
					FROM (
						SELECT AVG(salary) avg_sal
						FROM employees
						GROUP BY department_id
						) t_dept_avg_sal
					)
		);
#方式2
SELECT *
FROM departments
WHERE department_id = (
		SELECT department_id
		FROM employees
		GROUP BY department_id
		HAVING AVG(salary) <= ALL(
					SELECT AVG(salary)
					FROM employees
					GROUP BY department_id
					)
		);
#方式3:LIMIT
SELECT *
FROM departments
WHERE department_id = (
		SELECT department_id
		FROM employees
		GROUP BY department_id
		HAVING AVG(salary) = (
					SELECT AVG(salary) avg_sal
					FROM employees
					GROUP BY department_id
					ORDER BY avg_sal ASC
					LIMIT 0,1
					)
			)
#方式4
SELECT d.*
FROM departments d, (
		SELECT department_id, AVG(salary) avg_sal
		FROM employees
		GROUP BY department_id
		ORDER BY avg_sal ASC
		LIMIT 0,1
		) t_dept_avg_sal
WHERE d.department_id = t_dept_avg_sal.department_id;



#9.查询平均工资最低的部门信息和该部门的平均工资(相关子查询) 
#方式1:
SELECT d.*,(SELECT AVG(salary) FROM employees WHERE department_id = d.`department_id`) avg_sal
FROM departments d
WHERE department_id = (
			SELECT department_id
			FROM employees
			GROUP BY department_id
			HAVING AVG(salary ) = (
						SELECT MIN(avg_sal)
						FROM (
							SELECT AVG(salary) avg_sal
							FROM employees
							GROUP BY department_id
							) t_dept_avg_sal

						)
			);

#方式2:

SELECT d.*,(SELECT AVG(salary) FROM employees WHERE department_id = d.`department_id`) avg_sal
FROM departments d
WHERE department_id = (
			SELECT department_id
			FROM employees
			GROUP BY department_id
			HAVING AVG(salary ) <= ALL(
						SELECT AVG(salary)
						FROM employees
						GROUP BY department_id
						)
			);

#方式3: LIMIT

SELECT d.*,(SELECT AVG(salary) FROM employees WHERE department_id = d.`department_id`) avg_sal
FROM departments d
WHERE department_id = (
			SELECT department_id
			FROM employees
			GROUP BY department_id
			HAVING AVG(salary ) =(
						SELECT AVG(salary) avg_sal
						FROM employees
						GROUP BY department_id
						ORDER BY avg_sal ASC
						LIMIT 1		
						)
			);

#方式4:

SELECT d.*,(SELECT AVG(salary) FROM employees WHERE department_id = d.`department_id`) avg_sal
FROM departments d,(
		SELECT department_id,AVG(salary) avg_sal
		FROM employees
		GROUP BY department_id
		ORDER BY avg_sal ASC
		LIMIT 0,1
		) t_dept_avg_sal
WHERE d.`department_id` = t_dept_avg_sal.department_id

#10.查询平均工资最高的 job 信息 
#方式1:
SELECT *
FROM jobs
WHERE job_id = (
		SELECT job_id
		FROM employees
		GROUP BY job_id
		HAVING AVG(salary) = (
					SELECT MAX(avg_sal)
					FROM (
						SELECT AVG(salary) avg_sal
						FROM employees
						GROUP BY job_id
						) t_job_avg_sal
					)
		);
#方式2:
SELECT *
FROM jobs
WHERE job_id = (
		SELECT job_id
		FROM employees
		GROUP BY job_id
		HAVING AVG(salary) >= ALL(
				     SELECT AVG(salary) 
				     FROM employees
				     GROUP BY job_id
				     )
		);
#方式3:
SELECT *
FROM jobs
WHERE job_id = (
		SELECT job_id
		FROM employees
		GROUP BY job_id
		HAVING AVG(salary) =(
				     SELECT AVG(salary) avg_sal
				     FROM employees
				     GROUP BY job_id
				     ORDER BY avg_sal DESC
				     LIMIT 0,1
				     )
		);
#方式4:
SELECT j.*
FROM jobs j,(
		SELECT job_id,AVG(salary) avg_sal
		FROM employees
		GROUP BY job_id
		ORDER BY avg_sal DESC
		LIMIT 0,1		
		) t_job_avg_sal
WHERE j.job_id = t_job_avg_sal.job_id

#11.查询平均工资高于公司平均工资的部门有哪些? 
SELECT department_id
FROM employees
WHERE department_id IS NOT NULL
GROUP BY department_id
HAVING AVG(salary) > (
		SELECT AVG(salary)
		FROM employees
		);

#12.查询出公司中所有 manager 的详细信息 
#方式1:自连接
SELECT DISTINCT mgr.employee_id,mgr.last_name,mgr.job_id,mgr.department_id
FROM employees emp JOIN employees mgr
ON emp.manager_id = mgr.employee_id;

#方式2:子查询
SELECT employee_id,last_name,job_id,department_id
FROM employees
WHERE employee_id IN (
			SELECT DISTINCT manager_id
			FROM employees
			);
#方式3:使用EXISTS
SELECT employee_id,last_name,job_id,department_id
FROM employees e1
WHERE EXISTS (
	       SELECT *
	       FROM employees e2
	       WHERE e1.`employee_id` = e2.`manager_id`
	     );
	     
	     

#13.各个部门中 最高工资中最低的那个部门的 最低工资是多少? 
#方式1:
SELECT MIN(salary)
FROM employees
WHERE department_id = (
			SELECT department_id
			FROM employees
			GROUP BY department_id
			HAVING MAX(salary) = (
						SELECT MIN(max_sal)
						FROM (
							SELECT MAX(salary) max_sal
							FROM employees
							GROUP BY department_id
							) t_dept_max_sal
						)
			);

SELECT *
FROM employees
WHERE department_id = 10;
#方式2:
SELECT MIN(salary)
FROM employees
WHERE department_id = (
			SELECT department_id
			FROM employees
			GROUP BY department_id
			HAVING MAX(salary) <= ALL (
						SELECT MAX(salary)
						FROM employees
						GROUP BY department_id
						)
			);
#方式3:
SELECT MIN(salary)
FROM employees
WHERE department_id = (
			SELECT department_id
			FROM employees
			GROUP BY department_id
			HAVING MAX(salary) = (
						SELECT MAX(salary) max_sal
						FROM employees
						GROUP BY department_id
						ORDER BY max_sal ASC
						LIMIT 0,1
						)
			);	
#方式4:
SELECT MIN(salary)
FROM employees e,(
		SELECT department_id,MAX(salary) max_sal
		FROM employees
		GROUP BY department_id
		ORDER BY max_sal ASC
		LIMIT 0,1
		) t_dept_max_sal
WHERE e.department_id = t_dept_max_sal.department_id

#14.查询平均工资最高的部门的 manager 的详细信息: last_name, department_id, email, salary 
#方式1:
SELECT last_name, department_id, email, salary
FROM employees
WHERE employee_id IN ANY (
			SELECT DISTINCT manager_id
			FROM employees
			WHERE department_id = (
						SELECT department_id
						FROM employees
						GROUP BY department_id
						HAVING AVG(salary) = (
									SELECT MAX(avg_sal)
									FROM (
										SELECT AVG(salary) avg_sal
										FROM employees
										GROUP BY department_id
										) t_dept_avg_sal
									)
						)
			);
#方式2:
SELECT last_name, department_id, email, salary
FROM employees
WHERE employee_id = ANY (
			SELECT DISTINCT manager_id
			FROM employees
			WHERE department_id = (
						SELECT department_id
						FROM employees
						GROUP BY department_id
						HAVING AVG(salary) >= ALL (
								SELECT AVG(salary) avg_sal
								FROM employees
								GROUP BY department_id
								)
						)
			);
#方式3:
SELECT last_name, department_id, email, salary
FROM employees
WHERE employee_id IN (
			SELECT DISTINCT manager_id
			FROM employees e,(
					SELECT department_id,AVG(salary) avg_sal
					FROM employees
					GROUP BY department_id
					ORDER BY avg_sal DESC
					LIMIT 0,1
					) t_dept_avg_sal
			WHERE e.`department_id` = t_dept_avg_sal.department_id
			);

#15. 查询部门的部门号,其中不包括job_id是"ST_CLERK"的部门号 
#方式1:
SELECT department_id
FROM departments
WHERE department_id NOT IN (
			SELECT DISTINCT department_id
			FROM employees
			WHERE job_id = 'ST_CLERK'
			);
#方式2:
SELECT department_id
FROM departments d
WHERE NOT EXISTS (
		SELECT *
		FROM employees e
		WHERE d.`department_id` = e.`department_id`
		AND e.`job_id` = 'ST_CLERK'
		);


#16. 选择所有没有管理者的员工的last_name 
SELECT last_name
FROM employees e
WHERE NOT EXISTS (
		SELECT employee_id
		FROM employees m
		WHERE e.manager_id = m.employee_id
		);

#17.查询员工号、姓名、雇用时间、工资,其中员工的管理者为 'De Haan' 
#方式1:
SELECT employee_id,last_name,hire_date,salary
FROM employees
WHERE manager_id IN (
		SELECT employee_id
		FROM employees
		WHERE last_name = 'De Haan'
		);
#方式2:
SELECT employee_id,last_name,hire_date,salary
FROM employees e1
WHERE EXISTS (
		SELECT *
		FROM employees e2
		WHERE e1.`manager_id` = e2.`employee_id`
		AND e2.last_name = 'De Haan'
		); 

#18.查询各部门中工资比本部门平均工资高的员工的员工号, 姓名和工资(相关子查询)
#方式1:使用相关子查询
SELECT last_name,salary,department_id
FROM employees e1
WHERE salary > (
		SELECT AVG(salary)
		FROM employees e2
		WHERE department_id = e1.`department_id`
		);
#方式2:在FROM中声明子查询
SELECT e.last_name,e.salary,e.department_id
FROM employees e,(
		SELECT department_id,AVG(salary) avg_sal
		FROM employees
		GROUP BY department_id) t_dept_avg_sal
WHERE e.department_id = t_dept_avg_sal.department_id
AND e.salary > t_dept_avg_sal.avg_sal
 

#19.查询每个部门下的部门人数大于 5 的部门名称(相关子查询) 
#方式1
SELECT department_name
FROM departments d, (
		SELECT department_id, COUNT(*) num
		FROM employees
		GROUP BY department_id
		) dept_num
WHERE d.department_id = dept_num.department_id
AND num > 5
#方式2
SELECT department_name
FROM departments d
WHERE 5 < (
	   SELECT COUNT(*)
	   FROM employees e
	   WHERE d.department_id = e.`department_id`
	  );


#20.查询每个国家下的部门个数大于 2 的国家编号(相关子查询)
SELECT country_id
FROM locations l
WHERE 2 < (
	   SELECT COUNT(*)
	   FROM departments d
	   WHERE l.`location_id` = d.`location_id`
	 );

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