[大数据]将任意多个键值对转换成Json对象

fastjson

public class JsonTest {
    public static JSONObject fun(Object... objs){
        JSONObject jsonObject = new JSONObject();
        for (int i=0;i<objs.length;i+=2) {
            jsonObject.put((String) objs[i],objs[i+1]);
        }

        return jsonObject;
    }

    public static void main(String[] args) {
        Dept dept = DataUtil.build(Dept.class);

        Dept dept1 = DataUtil.build(Dept.class);
        Dept dept2 = DataUtil.build(Dept.class);
        Dept dept3 = DataUtil.build(Dept.class);
        List<Dept> deptList = List.of(dept1,dept2,dept3);

        JSONObject jsonObject = fun("dept", dept, "deptList", deptList);
        System.out.println(jsonObject);
    }
}

jackson

public class JsonTest {
    public static ObjectNode fun(Object... objs){
        ObjectMapper   objectMapper = new ObjectMapper();
        ObjectNode objectNode = objectMapper.createObjectNode();
        for (int i=0;i<objs.length;i+=2) {
            objectNode.putPOJO((String) objs[i],objs[i+1]);
        }

        return objectNode;
    }

    public static void main(String[] args) {
        Dept dept = DataUtil.build(Dept.class);

        Dept dept1 = DataUtil.build(Dept.class);
        Dept dept2 = DataUtil.build(Dept.class);
        Dept dept3 = DataUtil.build(Dept.class);
        List<Dept> deptList = List.of(dept1,dept2,dept3);

        ObjectNode objectNode = fun("dept", dept, "deptList", deptList);
        System.out.println(objectNode);
    }
}

程序最终结果