[移动开发]安卓将字符串互转二进制数组

字符串转化为二进制数组

 String s = "我是山东师范大学的一名学生。";
        byte[] nn = new byte[0];
        try {
            nn = (s).getBytes("UTF-8");//可更改为Unicode、ASCII编码
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        }
        int wlen1= nn.length;
        String wm1 ="";
        for (int k = 0; k < wlen1; k++) {
            byte b = nn[k];
            String result = "";
            byte a = b;
            for (int i = 0; i < 8; i++) {
                byte c = a;
                a = (byte) (a >> 1);//每移一位如同将10进制数除以2并去掉余数。
                a = (byte) (a << 1);
                if (a == c) {
                    result = "0" + result;
                } else {
                    result = "1" + result;
                }
                a = (byte) (a >> 1);
            }
            wm1 =new StringBuilder(wm1).append(result).toString();
        }
        char[] wm2=wm1.toCharArray();
        int []wm3=new int[wm1.length()];
        for (int k = 0; k < wm1.length(); k++) {
            wm3[k] =wm2[k]-48;//减去字符0的ascii码
        }

二进制数组转换成字符串

char []wm5=new char[wm1.length()];
        for (int k = 0; k < wm1.length(); k++) {
            wm5[k] = (char)(wm3[k]+'0');//
        }
        String wm4=String.valueOf(wm5);
        int size = wm1.length()/8;
        //定义接收数组
        byte[] bytes1 = new byte[size];
        for (int i = 0; i < size; i++) {
            //每次截取8位计算
            String tmp = wm4.substring(8*i,8*(i+1));
            int tmpInt = Integer.parseInt(tmp,2);
            byte tmpByte = (byte)(tmpInt & 0xff);
            bytes1[i] = tmpByte;
        }
        String str = new String(bytes1, Charset.forName("UTF-8"));