[移动开发]android IntentService

继承Service,启动肯定也是startService

 Intent intent=new Intent(this,Task.class);
        startService(intent);

执行后，会调起service，service中的：onStartCommand将会调用；即：

    @Override
    public int onStartCommand(@Nullable Intent intent, int flags, int startId) {
        onStart(intent, startId);
        return mRedelivery ? START_REDELIVER_INTENT : START_NOT_STICKY;
    }

继续执行：onStart(intent, startId);

    @Override
    public void onStart(@Nullable Intent intent, int startId) {
        Message msg = mServiceHandler.obtainMessage();
        msg.arg1 = startId;
        msg.obj = intent;
        mServiceHandler.sendMessage(msg);
    }

这里将intent传到handler中：

    private volatile ServiceHandler mServiceHandler;
    private String mName;
    private boolean mRedelivery;

    private final class ServiceHandler extends Handler {
        public ServiceHandler(Looper looper) {
            super(looper);
        }

        @Override
        public void handleMessage(Message msg) {
            onHandleIntent((Intent)msg.obj);
            stopSelf(msg.arg1);
        }
    }

则调用handleMessage中的onHandleIntent((Intent)msg.obj);和stopSelf(msg.arg1)（停止自身service）;

  @WorkerThread
    protected abstract void onHandleIntent(@Nullable Intent intent);

抽象方法，凡是继承intentservice的类，都要实现该方法，如下：

public class Task extends IntentService {
    /**
     * Creates an IntentService.  Invoked by your subclass's constructor.
     *
     * @param name Used to name the worker thread, important only for debugging.
     */
    public Task(String name) {
        super(name);
    }

    @Override
    protected void onHandleIntent(@Nullable Intent intent) {

    }
}

即，在startService之后，会调用onHandleIntent方法，