[开发工具]leetcode1116 本地运行方法 IDEA多线程打断点 切换线程

题目链接leetcode
这种多线程题总是很难在本地验证 然后打断点来排错，下面提供一下此题的本地实现方法
废话不多说 上代码

1.先自定义一个需要的工具类

import java.util.function.IntConsumer;

//此方法用来执行打印操作
public class myIntConsumer implements IntConsumer {
    @Override
    public void accept(int value) {
        System.out.println(value);
    }
}

2.然后上主类 顺便提供了semaphore的解法

import java.util.concurrent.Semaphore;

public class lk1116 {
    Semaphore zero = new Semaphore(1);
    Semaphore even = new Semaphore(0);
    Semaphore odd = new Semaphore(0);
    private int n;
    public volatile int x = 0;
	
	//在构造方法中来新启3个线程调用zero odd even方法 分别起名零、奇、偶
    public lk1116(int n) throws InterruptedException {
        System.out.println("创建对象了");
        this.n = n;
        new Thread(() -> {
            try {
                zero(new myIntConsumer());
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
                ,"零").start();
        new Thread(() -> {
            try {
                even(new myIntConsumer());
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
                ,"偶").start();
        new Thread(() -> {
            try {
                odd(new myIntConsumer());
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
                ,"奇").start();
    }

    // printNumber.accept(x) outputs "x", where x is an integer.
    public void zero(myIntConsumer printNumber) throws InterruptedException {
        System.out.println("进来了零方法");
        while (x < n) {
            zero.acquire();
            printNumber.accept(0);
            x++;
            if ((x & 1) == 1) {
                odd.release();
            }else even.release();
        }
        printNumber.accept(n);
        if ((n&1)==1){
            even.release();
        }else odd.release();
    }

    public void even(myIntConsumer printNumber) throws InterruptedException {
        while (x < n) {
            even.acquire();
            if (x!=n) printNumber.accept(x);
            zero.release();
        }
    }

    public void odd(myIntConsumer printNumber) throws InterruptedException {
        while (x < n) {
            odd.acquire();
            if (x!=n) printNumber.accept(x);
            zero.release();
        }
    }
}

3.调用

public static void main(String[] args) throws InterruptedException {
        lk1116 lk1116 = new lk1116(5);
}

最后打印

最后这种多线程打断点一定要将断点改为线程级别的，如下图为IDEA修改断点为线程级

然后线程间切换使用以下方式切换