https://leetcode-cn.com/problems/palindrome-linked-list/
难度简单1087
给你一个单链表的头节点?head ?,请你判断该链表是否为回文链表。如果是,返回?true ?;否则,返回?false ?。
示例 1:
输入:head = [1,2,2,1]
输出:true
示例 2:
输入:head = [1,2]
输出:false
提示:
- 链表中节点数目在范围
[1, 105] ?内 0 <= Node.val <= 9
进阶:你能否用?O(n) ?时间复杂度和?O(1) ?空间复杂度解决此题?
通过次数293,160提交次数595,792
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution {
public boolean isPalindrome(ListNode head) {
List<Integer> num = new ArrayList<Integer>();
while(head!=null)
{
num.add(head.val);
head = head.next;
}
for(int i=0,j=num.size()-1;i<j;i++,j--)
{
if(num.get(i)!=num.get(j)) return false;
}
return true;
}
}
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