[数据结构与算法]C语言实现扫雷小游戏

首先来规划一下扫雷游戏实现的几个步骤：
初始化棋盘：二维数组的遍历及赋值
为了后续代码的简洁方便，我们用’0’来初始化

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
	int i = 0;
	int j = 0;
	for (i = 0; i < rows; i++)
	{
		for (j = 0; j < cols; j++)
		{
			board[i][j] = set;
		}
	}
}

布置雷的信息：应用随机函数进行赋值

void SetMine(char mine[ROWS][COLS], int row, int col)
{
	int count = EASY_COUNT;
	while (count)
	{
		int x = rand() % row + 1;
		int y = rand() % col + 1;

		if (mine[x][y] == '0')
		{
			mine[x][y] = '1';
			count--;
		}
	}
}

排查雷：

void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	while (win<row*col- EASY_COUNT)
	{
		printf("请输入要排查的坐标->");
		scanf("%d %d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (mine[x][y] == '1')
			{
				printf("很遗憾你被炸死了\n");
				DisplayBoard(mine, row, col);
				break;
			}
			else
			{
				//计算x,y坐标周围有几个雷
				int n=get_mine_count(mine, x, y);
				show[x][y] = n + '0';
				DisplayBoard(show, row, col);
				win++;

			}
			
			
		}
		else
			printf("输入坐标错误，请重新输入\n");

	}
	if (win == row * col - EASY_COUNT)
	{
		printf("恭喜你，排雷成功\n");
		DisplayBoard(mine, row, col);
	}
}

下面是游戏实现的完整代码，依旧是分为了3个版块，为了更好的管理代码，提高代码的可读性和可移植性
game2.h

#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#define ROW 9
#define COL 9
#define  EASY_COUNT 10

#define ROWS ROW+2
#define COLS COL+2

//初始化棋盘
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
//打印棋盘
void DisplayBoard(char board[ROWS][COLS], int row, int col);
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col);
//排查雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

game2.c

#include "game2.h"

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
	int i = 0;
	int j = 0;
	for (i = 0; i < rows; i++)
	{
		for (j = 0; j < cols; j++)
		{
			board[i][j] = set;
		}
	}
}
void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
	int i = 0;
	int j = 0;
	for (i = 0; i <= col; i++)
	{
		printf("%d ", i);
	}
	printf("\n");
	for (i = 1; i <= row; i++)
	{
		printf("%d ", i);
		for (j = 1; j <= col; j++)
		{
			printf("%c ", board[i][j]);
		}
		printf("\n");

	}
}
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col)
{
	int count = EASY_COUNT;
	while (count)
	{
		int x = rand() % row + 1;
		int y = rand() % col + 1;

		if (mine[x][y] == '0')
		{
			mine[x][y] = '1';
			count--;
		}
	}
}
static int get_mine_count(char mine[ROWS][COLS], int x, int y)
{
	return mine[x - 1][y] + 
		mine[x - 1][y - 1] +
		mine[x][y - 1] + 
		mine[x + 1][y] + 
		mine[x + 1][y + 1] +
		mine[x][y + 1] + 
		mine[x - 1][y + 1]+
		mine[x+1][y-1]-8*'0';
}


void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	while (win<row*col- EASY_COUNT)
	{
		printf("请输入要排查的坐标->");
		scanf("%d %d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (mine[x][y] == '1')
			{
				printf("很遗憾你被炸死了\n");
				DisplayBoard(mine, row, col);
				break;
			}
			else
			{
				//计算x,y坐标周围有几个雷
				int n=get_mine_count(mine, x, y);
				show[x][y] = n + '0';
				DisplayBoard(show, row, col);
				win++;

			}
			
			
		}
		else
			printf("输入坐标错误，请重新输入\n");

	}
	if (win == row * col - EASY_COUNT)
	{
		printf("恭喜你，排雷成功\n");
		DisplayBoard(mine, row, col);
	}
}

test.c

#include "game2.h"
void menu()
{
	printf("**************************\n");
	printf("*******   1.play   *******\n");
	printf("*******   0.exit   *******\n");
	printf("**************************\n");

}

void game()
{
	//创建数组
	char mine[ROWS][COLS] = { 0 };//存放布置好的雷的信息
	char show[ROWS][COLS] = { 0 };//存放排查出的雷的信息

	//初始化mine数组全部为‘0’
	InitBoard(mine, ROWS, COLS, '0');
	//初始化show数组全部为‘0’
	InitBoard(show, ROWS, COLS, '*');

	//打印棋盘
	//DisplayBoard(mine, ROW, COL);

	//布置雷
	SetMine(mine, ROW, COL);
	DisplayBoard(show, ROW, COL);

	//DisplayBoard(mine, ROW, COL);

	//排查雷
	FindMine(mine, show, ROW, COL);
}
void test()
{
	int input = 0;
	srand((unsigned int)time(NULL));
	do
	{
		menu();
		printf("请选择->");
		scanf("%d", &input);
		switch (input)
		{
		case 1:
			game();
			break;

		case 0:
			printf("退出游戏\n");
			break;

		default:
			printf("选择错误\n");
			break;
		}
	} while (input);
}
int main()
{
	test();
	return 0;

}