前言

hello，大家好。这期文章博主和大家分享一下合并两个有序线性表的方法，希望对大家有所帮助。

1. 题目

在这里插入图片描述

2. 代码

2.1 LinkList.h

#ifndef LINKLIST_H
#define LINKLIST_H
#include<iostream>
#include<vector>
using namespace std;


template <class T>
struct Node
{
	T data;
	Node<T> *next;
};
template <class T>
class LinkList
{
public:
	LinkList();
	LinkList(T a[], int n);
	~LinkList();
	friend void LinkListMerge(LinkList<T> &L1, LinkList<T> &L2)
	{
		
		Node<T>*p1 = L1.head->next;
		Node<T>*p2 = L2.head->next;
		Node<T>*p3 = L1.head;
		vector<int>l;
		while ((p1 != NULL) && (p2 != NULL))
		{
			if ((p1->data)<(p2->data))
			{
				l.push_back(p1->data);
				p3->next = p1;	
				p1 = p1->next;
				p3 = p3->next;
			}
			else
			{
				l.push_back(p2->data);
				p3->next = p2;   
				p2 = p2->next;
				p3 = p3->next;
			}
		}
		if (p1 != NULL)
			p3->next = p1;
		if (p2 != NULL)
			p3-> next = p2;
		p3 = p3->next;
		while (p3 != NULL)
		{
			l.push_back(p3->data);
			p3=p3->next;
		}
		for (auto e : l)
		{

 			cout << e << " ";
		}
		cout << endl;
	}
private:
	Node<T> *head;
};

#endif

2.2 LinkList.cpp

#define _CRT_SECURE_NO_WARNINGS   1
#include"LinkList.h"

template <class T>
LinkList<T>::LinkList()
{
	head = new Node<T>;
	head->next = NULL;
}
template <class T>
LinkList<T>::LinkList(T a[], int n)
{
	Node<T>* rear, *s;
	head = new Node<T>;
	rear = head;
	for (int i = 0; i < n; i++)
	{
		s = new Node<T>;
		s->data = a[i];
		rear->next = s;
		rear = s;
	}
	rear->next = NULL;
}

template <class T>
LinkList<T>:: ~LinkList()
{
	Node<T>* p, *q;
	p = head;
	while (p)
	{
		q = p;
		p = p->next;
		delete q;

	}
	head = NULL;
}

2.3 SeqList.h

#ifndef SEQLIST_H
#define SEQLIST_H
#include<vector>
#include<iostream>
using namespace std;


template <class T, int MaxSize>  
class SeqList
{
	T data[MaxSize];        
	int length;              
public:
	SeqList();              
	SeqList(T a[], int n);  
	friend void SeqListMerge(SeqList<T, MaxSize> &S1, SeqList<T, MaxSize>&S2)
	{
		vector<int>s;
		int i = 0;
		int j = 0;
		while (i < S1.length&&j < S2.length)
		{
			if (S1.data[i] < S2.data[j])
			{
				s.push_back(S1.data[i]);
				i++;
			}
			else
			{
				s.push_back(S2.data[j]);
				j++;
			}
		}
		if (i < S1.length)
		{
			for (int k = i; k < S1.length; k++)
				s.push_back(S1.data[k]);
		}
		else
		{
			for (int k = j; k < S2.length; k++)
				s.push_back(S2.data[k]);
		}
		for (auto e : s)
		{
			cout << e << " ";
		}
		cout << endl;
	}
};

#endif

2.4 SeqList.cpp

#define _CRT_SECURE_NO_WARNINGS   1

#include"SeqList.h"
#include<iostream>
template <class T, int MaxSize>

SeqList<T, MaxSize >::SeqList()
{
	length = 0;
}

template <class T, int MaxSize>
SeqList<T, MaxSize>::SeqList(T a[], int n)
{
	if (n>MaxSize) 
	{ 
		cerr << "参数非法"; exit(1); 
	}
	for (int i = 0; i<n; i++)
		data[i] = a[i];
	length = n;
}

2.5 test.cpp

#define _CRT_SECURE_NO_WARNINGS   1
#include"LinkList.cpp"
#include"SeqList.cpp"
#include<iostream>
using namespace std;

void menu()
{
	cout << "|--------------------------------------------|" << endl;
	cout << "|欢迎来到两个有序线性表的合并，请选择实现方式|" << endl;
	cout << "|******************  0.退出    **************|" << endl;
	cout << "|******************  1.顺序表  **************|" << endl;
	cout << "|******************  2.链表    **************|" << endl;
	cout << "|--------------------------------------------|" << endl;
}

int main()
{
	cout << "请输入第一个有序线性表的长度和内容\n" << endl;
	int *a;
	int n;
	cin >> n;
	a = new int[n];
	for (int i = 0; i < n; i++)
	{
		cin >> a[i];
	}
	cout << "请输入第二个有序线性表的长度和内容\n" << endl;
	int *b;
	int m;
	cin >> m;
	b = new int[m];
	for (int i = 0; i < m; i++)
	{
		cin >> b[i];
	}
	SeqList<int, 20>Seq1(a, n);
	SeqList<int, 20>Seq2(b, m);
	LinkList<int> Link1(a, n);
	LinkList<int>Link2(b, m);
	int input = 0;
	do
	{
		menu();
		cin >> input;
		switch (input)
		{
		case 1:
			SeqListMerge(Seq1,Seq2);
			break;
		case 2:
			LinkListMerge(Link1, Link2);
			break;
		case 0:
			cout << "感谢您的使用，程序退出" << endl;
			break;
		default:
			cout << "输入错误，请重新输入，或者，您可以选择0来终止程序" << endl;
		}
	} while (input);
	return 0;
}