约瑟夫环问题全部Java代码如下:
package DataStructures.linkedList;
public class Josepfu {
public static void main(String[] args) {
CircleSingleLinkedList c = new CircleSingleLinkedList();
c.addBoy(5);
c.showBoy();
c.countBoy(1,2,5);
}
}
//创建一个单向循环链表
class CircleSingleLinkedList{
private Boy first = null;
public void addBoy(int nums){
if( nums < 2 ){
System.out.println("nums的值不正确!");
return;
}
Boy curBoy = null;
for (int i = 1; i <= nums; i++) {
Boy boy = new Boy(i);
if( i == 1 ){
first = boy;
first.setNext(first);
curBoy = first;
} else {
curBoy.setNext(boy);
boy.setNext(first);
curBoy = boy;
}
}
}
//遍历当前链表
public void showBoy(){
if( first == null ){
System.out.println("没有小孩!");
return;
}
Boy curBoy = first;
while( true ){
System.out.printf("小孩编号:%d\n",curBoy.getNo());
if(curBoy.getNext() == first){
break;
}
curBoy = curBoy.getNext();
}
}
//根据用户输入,计算出小孩出圈的顺序
/**
*
* @param startNo 表示从第几个小孩开始数数
* @param countNum 表示数几下
* @param nums 表示最开始有多少小孩在圈中
*/
public void countBoy(int startNo, int countNum, int nums){
if( first == null || startNo < 1 || startNo > nums ){
System.out.println("输入数据有误,请重新输入...");
return;
}
Boy helper = first;
while(true){
if( helper.getNext() == first ){
break;
}
helper = helper.getNext();
}
//小孩报数前,先让first和helper移动(startNo - 1)次
for (int i = 0; i < startNo - 1; i++) {
first = first.getNext();
helper = helper.getNext();
}
//开始报数出圈
while( true ){
if( helper == first ){
break;
}
for (int i = 0; i < countNum - 1; i++) {
first = first.getNext();
helper = helper.getNext();
}
System.out.printf("小孩%d出圈...\n",first.getNo());
helper.setNext(first.getNext());
first = first.getNext();
}
System.out.printf("最后留在圈中的小孩为%d\n",first.getNo());
}
}
//创建一个Boy类,表示一个节点
class Boy{
private int no;
private Boy next;
public Boy(int no){
this.no = no;
}
public int getNo() {
return no;
}
public void setNo(int no) {
this.no = no;
}
public Boy getNext() {
return next;
}
public void setNext(Boy next) {
this.next = next;
}
}
执行结果如图:
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