[数据结构与算法]【搜索】（零散刷题记录）

P1451 求细胞数量

题目链接：P1451 求细胞数量 - 洛谷 | 计算机科学教育新生态 (luogu.com.cn)

bfs:

#include <iostream>
#include <string>
#include <queue>
using namespace std;

int dx[4] = {1, -1, 0, 0};

int dy[4] = {0, 0, 1, -1};
string s[105];
bool vis[105][105];

struct point {
	int x, y;
};

int main() {
	int n, m, ans = 0;
	cin >> n >> m;
	for (int i = 0; i < n; i++) {
		cin >> s[i];
	}
	queue<point>q;
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			if (s[i][j] != '0' && vis[i][j] == 0) {
				ans++;
				vis[i][j] = 1;
				point p;
				p.x = i, p.y = j;
				q.push(p);
				while (!q.empty()) {
					for (int k = 0; k < 4; k++) {
						int xx = q.front().x + dx[k];
						int yy = q.front().y + dy[k];
						if (xx >= 0 && xx < n && yy >= 0 && yy < m && vis[xx][yy] == 0 && s[xx][yy] != '0') {
							point t;
							t.x = xx, t.y = yy;
							q.push(t);
							vis[xx][yy] = 1;
						}
					}
					q.pop();
				}
			}
		}
	}
	cout << ans;
	return 0;
}

P1460 [USACO2.1]健康的荷斯坦奶牛 Healthy Holsteins

题目链接：P1460 [USACO2.1]健康的荷斯坦奶牛 Healthy Holsteins - 洛谷 | 计算机科学教育新生态 (luogu.com.cn)

dfs:?

#include <iostream>
#include <cstring>
using namespace std;
int v, g, p = (1 << 29), cnt;
int a[30], t[30];
int b[20][30];
int ans[20], minn[20];

bool check() {
	for (int i = 1; i <= v; i++) {
		if (t[i] < a[i]) {
			return false;
		}
	}
	return true;
}

void dfs(int i) {
	if (i > g ) {
		if (p > cnt && check()) {
			p = cnt;
			for (int j = 1; j <= p; j++) {
				ans[j] = minn[j];
			}
		}
		return;
	}
	cnt++;
	minn[cnt] = i;
	for (int j = 1; j <= v; j++) {
		t[j] += b[i][j];
	}
	dfs(i + 1);
	minn[cnt] = 0;
	cnt--;
	for (int j = 1; j <= v; j++) {
		t[j] -= b[i][j];
	}
	dfs(i + 1);
}

int main() {
	cin >> v;
	for (int i = 1; i <= v; i++) {
		cin >> a[i];
	}
	cin >> g;
	for (int i = 1; i <= g; i++) {
		for (int j = 1; j <= v; j++) {
			cin >> b[i][j];
		}
	}
	dfs(1);
	cout << p << ' ';
	for (int i = 1; i <= p; i++) {
		cout << ans[i] << ' ';
	}
	return 0;
}

P2372 yyy2015c01挑战算周长

题目链接：P2372 yyy2015c01挑战算周长 - 洛谷 | 计算机科学教育新生态 (luogu.com.cn)

bfs:?

#include <iostream>
#include <queue>
using namespace std;

int dx[8] = {0, 0, 1, -1, 1, 1, -1, -1};

int dy[8] = {1, -1, 0, 0, -1, 1, 1, -1};
char mapp[30][30];
bool vis[30][30];

int main() {
	int m, n, x, y, ans = 0;
	queue<pair<int, int>>q;
	cin >> m >> n >> x >> y;
	for (int i = 0; i < m; i++) {
		cin >> mapp[i];
	}
	q.push(make_pair(x - 1, y - 1));
	vis[x - 1][y - 1] = 1;
	while (!q.empty()) {
		for (int i = 0; i < 8; i++) {
			int xx = q.front().first + dx[i];
			int yy = q.front().second + dy[i];
			if (xx >= 0 && xx < m && yy >= 0 && yy < n && vis[xx][yy] == 0 && mapp[xx][yy] == 'X') {
				vis[xx][yy] = 1;
				q.push(make_pair(xx, yy));
			}
		}
		q.pop();
	}
	for (int i = 0; i < m; i++) {
		for (int j = 0; j < n; j++) {
			if (vis[i][j]) {
				for (int k = 0; k < 4; k++) {
					int xx = i + dx[k];
					int yy = j + dy[k];
					if (xx < 0 || xx >= m || yy < 0 || yy >= n || vis[xx][yy] == 0) {
						ans++;
					}
				}
			}
		}
	}
	cout << ans;
	return 0;
}