[游戏开发]用C语言实现一个简单地推箱子小游戏！！！！！！！（通俗易懂）

**

详细见注释

**

#include <stdlib.h>
#include <getch.h>

int main(int argc,const char* argv[])
{
	char map[8][8] ={
		{0,0,3,3,3,3,0,0},
		{0,0,3,5,5,3,0,0},
		{0,3,3,0,5,3,3,0},
		{0,3,0,0,4,5,3,0},
		{3,3,0,4,0,0,3,3},
		{3,0,0,0,4,4,0,3},
		{3,0,0,2,0,0,0,3},
		{3,3,3,3,3,3,3,3}
		};

	char m_x = 6,m_y = 3;

	for(;;)
	{
		int cnt = 0;
		system("clear");
		for(int i=0; i<8; i++)
		{
			for(int j=0; j<8; j++)
			{
				switch(map[i][j])
				{	//用特殊字符代表墙，人，箱子等等
					case 0:	printf("  "); break;
					case 2: printf("@ "); break;
					case 3:	printf("# "); break;
					case 4: printf("$ "); break;
					case 5: printf("O "); break;
					case 7: printf("@ "); break;
					case 9: printf("$ ");	cnt++;	 break;
				}
			}
			printf("\n");
		}

		if(4 == cnt)
		{
			printf("游戏胜利!\n");	
			return 0;
		}

		int p_x = 0, p_y = 0;

		switch(getch())
		{
			case 183:	p_x--; break;
			case 184:	p_x++; break;
			case 185:	p_y++; break;
			case 186:	p_y--; break;
		}
		if(0 == map[m_x+p_x][m_y+p_y] || 5 == map[m_x+p_x][m_y+p_y])
		{
			map[m_x+p_x][m_y+p_y] += 2;
			map[m_x][m_y] -= 2;
			m_x += p_x;
			m_y += p_y;
		}
		else if(4 == map[m_x+p_x][m_y+p_y] || 9 == map[m_x+p_x][m_y+p_y])
		{
			if(0 == map[m_x+2*p_x][m_y+2*p_y] || 
				5 == map[m_x+2*p_x][m_y+2*p_y])
			{
				map[m_x+2*p_x][m_y+2*p_y] += 4;
				map[m_x+p_x][m_y+p_y] -= 2;
				map[m_x][m_y] -= 2;
				m_x += p_x;
				m_y += p_y;
			}
		}
	}
}