[游戏开发]小游戏：推箱子与推箱子简化版

??在第一版的代码中，将人在目标点上以及箱子在目标点上另外输出，在后续的获取方向键并处理时，只需减去人和箱子的数字就可以刷新目标点的显示，不会出现“吃”目标点的情况。
??而在第二版的代码中，使用偏移值的改变来简化代码，只需通过方向键的按键活动来改变偏移值，就可实现通过两个嵌套的if语句来进行人、箱子、目标点的改变与刷新。
以下是第一版的推箱子代码：

#include <stdio.h>
#include <getch.h>
#include <stdlib.h>//system  头文件
int main(int argc,const char* argv[])
{
	//定义迷宫地图
	char map[8][8] = {
		{0,0,1,1,1,1,0,0},
		{0,0,1,4,4,1,0,0},
		{0,1,1,0,4,1,1,0},
		{1,1,1,0,3,4,1,0},
		{1,1,0,3,0,0,1,1},
		{1,0,0,1,3,3,0,1},
		{1,0,0,2,0,0,0,1},
		{1,1,1,1,1,1,1,1},
	};
	
	char m_x = 6,m_y = 3;

	int step = 0;
	for(;;)
	{
		int cnt = 0;
		system("clear");
		for(int i =0;i<8;i++)
		{
			for(int j =0;j<8;j++)
			{
				switch(map[i][j])
				{
					case 0:printf("  ");break;	
					case 1:printf("# ");break;	
					case 2:printf("@ ");break;	
					case 3:printf("$ ");break;	
					case 4:printf("0 ");break;	
					case 6:printf("@ ");break;//人在目标点上，显示人	
					case 7:printf("$ ");
							cnt++;
							break;//箱子在目标点上，显示箱子
				}
			}
			printf("\n");
		}
		if(cnt == 4)
		{
			printf("游戏结束，共走了%d步\n",step);
			return 0 ;
		}

		switch(getch())
		{
			case 183:
				if(0 == map[m_x-1][m_y] || 4  == map[m_x-1][m_y])
				{
					map[m_x-1][m_y] += 2;	
					map[m_x][m_y] -= 2;
					m_x--;
					step++;
				}
				else if(3 == map[m_x-1][m_y] || 7 == map[m_x-1][m_y])//箱子有可能在空地 有可能在目标点上
				{	
					if(0 == map[m_x-2][m_y] || 4  == map[m_x-2][m_y])
					{
						map[m_x-2][m_y] += 3;
						map[m_x-1][m_y] -= 1;
						map[m_x][m_y] -= 2;
						m_x--;//更新人的坐标
						step++;
					}
				}
				break;
			case 184:
				if(0 == map[m_x+1][m_y] || 4  == map[m_x+1][m_y])
				{
					map[m_x+1][m_y] += 2;	
					map[m_x][m_y] -= 2;
					m_x++;
					step++;
				}
				else if(3 == map[m_x+1][m_y] || 7 == map[m_x+1][m_y])//箱子有可能在空地 有可能在目标点上
				{	
					if(0 == map[m_x+2][m_y] || 4  == map[m_x+2][m_y])
					{
						map[m_x+2][m_y] += 3;
						map[m_x+1][m_y] -= 1;
						map[m_x][m_y] -= 2;
						m_x++;//更新人的坐标
						step++;
					}
				}
				break;
			case 185:
				if(0 == map[m_x][m_y+1] || 4  == map[m_x][m_y+1])
				{
					map[m_x][m_y+1] += 2;	
					map[m_x][m_y] -= 2;
					m_y++;
					step++;
				}
				else if(3 == map[m_x][m_y+1] || 7 == map[m_x][m_y+1])//箱子有可能在空地 有可能在目标点上
				{	
					if(0 == map[m_x][m_y+2] || 4  == map[m_x][m_y+2])
					{
						map[m_x][m_y+2] += 3;
						map[m_x][m_y+1] -= 1;
						map[m_x][m_y] -= 2;
						m_y++;//更新人的坐标
						step++;
					}
				}
				break;
			case 186:
				if(0 == map[m_x][m_y-1] || 4  == map[m_x][m_y-1])
				{
					map[m_x][m_y-1] += 2;	
					map[m_x][m_y] -= 2;
					m_y--;
					step++;
				}
				else if(3 == map[m_x][m_y-1] || 7 == map[m_x][m_y-1])//箱子有可能在空地 有可能在目标点上
				{	
					if(0 == map[m_x][m_y-2] || 4  == map[m_x][m_y-2])
					{
						map[m_x][m_y-2] += 3;
						map[m_x][m_y-1] -= 1;
						map[m_x][m_y] -= 2;
						m_y--;//更新人的坐标
						step++;
					}
				}
				break;
		}
	}
}

以下是第二版代码：

#include <stdio.h>
#include <getch.h>
#include <stdlib.h>//system  头文件
int main(int argc,const char* argv[])
{
	//定义迷宫地图
	char map[8][8] = {
		{0,0,1,1,1,1,0,0},
		{0,0,1,4,4,1,0,0},
		{0,1,1,0,4,1,1,0},
		{1,1,1,0,3,4,1,0},
		{1,1,0,3,0,0,1,1},
		{1,0,0,1,3,3,0,1},
		{1,0,0,2,0,0,0,1},
		{1,1,1,1,1,1,1,1},
	};
	
	char m_x = 6,m_y = 3;

	int step = 0;
	for(;;)
	{
		int cnt = 0;
		system("clear");
		for(int i =0;i<8;i++)
		{
			for(int j =0;j<8;j++)
			{
				switch(map[i][j])
				{
					case 0:printf("  ");break;	
					case 1:printf("# ");break;	
					case 2:printf("@ ");break;	
					case 3:printf("$ ");break;	
					case 4:printf("0 ");break;	
					case 6:printf("@ ");break;//人在目标点上，显示人	
					case 7:printf("$ ");
							cnt++;
							break;//箱子在目标点上，显示箱子
				}
			}
			printf("\n");
		}
		if(cnt == 4)
		{
			printf("游戏结束，共走了%d步\n",step);
			return 0 ;
		}
		int x = 0,y = 0;
		switch(getch())
		{
			case 183:
			x = -1;break;
			case 184:
			x = 1;break;
			case 185:
			y = 1;break;
			case 186:
			y = -1;break;
		}
		if(0 == map[m_x+x][m_y+y] || 4  == map[m_x+x][m_y+y])
		{
			map[m_x+x][m_y+y] += 2;	
			map[m_x][m_y] -= 2;
			m_x +=x;m_y +=y;
			step++;
		}
		else if(3 == map[m_x+x][m_y+y] || 7 == map[m_x+x][m_y+y])//箱子有可能在空地 有可能在目标点上
		{	
			if(0 == map[m_x+2*x][m_y+2*y] || 4  == map[m_x+2*x][m_y+2*y])
			{
				map[m_x+2*x][m_y+2*y] += 3;
				map[m_x+x][m_y+y] -= 1;
				map[m_x][m_y] -= 2;
				m_x += x; m_y +=y;//更新人的坐标
				step++;
			}
		}
	}
}

可以看到，代码量减少了将近一半。