前言
《扫雷》是一款大众类的益智小游戏，于1992年发行。游戏目标是在最短的时间内根据点击格子出现的数字找出所有非雷格子，同时避免踩雷，踩到一个雷即全盘皆输。一、初始化游戏菜单并导入头文件
1.
#include"mines.h"
void menu()
{
printf("-----------------------------------\n");
printf("------------1.开始游戏-------------\n");
printf("------------0.退出游戏-------------\n");
printf("-----------------------------------\n");
}
int main(void)
{
int input = 0;
do
{
neum();
printf("请输入:>");
scanf("%d", &input);
switch (input)
{
case 1:
{
system("cls");
game();
break;
}
case 0:
{
printf("退出游戏\n");
break;
}
default:
printf("选择错误请重选\n");
break;
}
} while (input);
return 0;
}
2.
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<time.h>
#define COUNT 10
#define ROW 10
#define COL 10
#define ROWS ROW+2
#define COLS COL+2
void lnitbrod(char broad[ROWS][COLS], int row, int col); //初始化棋盘
void lnitbrod2(char broad[ROWS][COLS], int row, int col); //初始化棋盘2
void Layoutbroad(char mine[ROWS][COLS], int row, int col, int count); //随机布置雷数
void showbroad(char broad[ROWS][COLS], int row, int col); //展示棋盘
void playgame(char broad[ROWS][COLS], char show[ROWS][COLS]); //主游戏函数
二、设计游戏函数
代码如下：
void game()
{
srand((unsigned int)time(NULL));//设置随机时间值
char broad[ROWS][COLS];
char show[ROWS][COLS];
lnitbrod(broad, ROWS, COLS);//初始化真棋盘
lnitbrod2(show, ROW, COL);//初始化展示棋盘
Layoutbroad(broad, ROW, COL, COUNT);//随机布置雷数 现是：10
showbroad(show, ROW, COL);//展示棋盘
playgame(broad, show);//判断游戏输赢机制
}
三、进入游戏函数并开始执行
代码如下：
#include"mines.h"
void lnitbrod(char broad[ROWS][COLS],int row,int col) //初始化
{
for (int i = 0; i < row;i++)
{
for (int j = 0; j < col; j++)
{
broad[i][j] = '0';
}
}
}
void lnitbrod2(char broad[ROWS][COLS], int row, int col)//初始化
{
for (int i = 1; i <= row; i++)
{
for (int j = 1; j <= col; j++)
{
broad[i][j] = '*';
}
}
}
void Layoutbroad(char mine[ROWS][COLS], int row, int col,int count) //随机布置雷数
{
while (count)
{
int x = rand() % row + 1;
int y = rand() % col + 1;
mine[x][y] = '1';
count--;
}
}
void showbroad(char broad[ROWS][COLS], int row, int col)//展示棋盘
{
printf(" ");
for (int i = 1; i <= row; i++)
{
printf("%d ", i);
}
printf("\n");
printf(" ");
for (int i = 0; i < row; i++)
{
printf("--");
}
printf("\n");
for (int i = 1; i <=row; i++)
{
printf("%2d|", i);
for (int j = 1; j <= col; j++)
{
printf(" %c", broad[i][j]);
}
printf("\n");
}
}
int getmine(char mine[ROWS][COLS], int i, int j)//获取真棋盘周围8个格子的雷数
{
return mine[i + 1][j] + mine[i - 1][j] + mine[i][j - 1] +
mine[i][j + 1] + mine[i + 1][j + 1] + mine[i - 1][j - 1] +
mine[i - 1][j + 1] + mine[i + 1][j - 1] - 8 * '0';
}
void Expand(char mine[ROWS][COLS], char show[ROWS][COLS], int x, int y, int* win)//递归展开函数
{
for (int i = -1; i < 2; i++)
{
for (int j = -1; j < 2; j++)
{
if (i != 0 || j != 0)
{
if (x + i >= 1 && x + i <= ROW && y + j >= 1 && y + j <= COL && mine[x + i][y + j] != '1')
{
if (show[x + i][y + j] == '*' && mine[x + i][y + j] == '0')
{
int count = getmine(mine, x + i, y + j);
if (count != 0)
{
show[x + i][y + j] = count + '0';
(*win)++;
}
else
{
show[x + i][y + j] = ' ';
Expand(mine, show, x + i, y + j, win);
(*win)++;
}
}
}
}
}
}
}
void gameover(char broad[ROWS][COLS], int row, int col)//如果游戏结束 则展示真棋盘
{
for (int i = 1; i <= row; i++)
{
for (int j = 1; j <= col; j++)
{
if (broad[i][j] == '1')
{
printf("* ");
}
else
{
printf("O ");
}
}
printf("\n");
}
}
void playgame(char broad[ROWS][COLS],char show[ROWS][COLS])//游戏机制主体函数
{
int x = 0;
int y = 0;
int count = 0;
int win = 0;
while (win<ROW*COL-count)
{
printf("请输入坐标(行数,列数):>");
scanf("%d %d", &x, &y);
if (x >= 1 && x <= ROW && y >= 1 && y <= COL)
{
if (broad[x][y] == '1')
{
printf("顺干爆炸，game over\n");
gameover(broad, ROW, COL);
return;
}
else
{
count = getmine(broad, x, y);
if (count != 0)
{
show[x][y] = count + '0';
}
else
{
show[x][y] = ' ';
system("cls");
Expand(broad, show, x, y, &win);
}
showbroad(show, ROW, COL);
}
}
else
{
printf("输入非法请重试\n");
}
}
if (win - ROW * COL - count == 0)
{
printf("恭喜排雷成功\n");
return;
}
}
总结
运行结果如下
开始菜单:
展示:
输入 5 5
游戏结束：
