[游戏开发]pygame编写井字棋游戏

环境：python
使用的第三方库：pygame
若为安装pygame请在终端输入"pip install pygame"安装pygame后再运行程序
废话不多说直接上代码（有注释！！！）

import pygame, sys # 声明 导入需要的模块
from pygame.locals import *
from math import pi

pygame.init()# 初始化pygame
screen = pygame.display.set_mode((700,700))# 设置窗口的大小，单位为像素
pygame.display.set_caption('井字棋')# 设置窗口的标题


# 定义基础颜色
BLACK = ( 0, 0, 0)
WHITE = (255, 255, 255)
RED = (255, 0, 0)
GREEN = ( 0, 255, 0)
BLUE = ( 0, 0, 255)

# 九个格子的位置（写死，有更好的方法请告诉我（肯定有））
box1=[50,50,195,195]
box2=[50,250,195,195]
box3=[50,450,195,195]
box4=[250,50,195,195]
box5=[250,250,195,195]
box6=[250,450,195,195]
box7=[450,50,195,195]
box8=[450,250,195,195]
box9=[450,450,195,195]
# 放进一个大的格子数组中
boxes=[box1,box2,box3,box4,box5,box6,box7,box8,box9]

# 绘制黑色作为背景
screen.fill(BLACK)
# 绘制棋盘
for i in range(0,9):
    pygame.draw.rect(screen, WHITE, boxes[i], 3)
# 棋子标识 1为圈 ，0为叉
status = 1
# 已经下了几颗棋子
number = 0
# 棋盘和棋子，0为空，1为圈，2为叉
nine = [[0,0,0],[0,0,0],[0,0,0]]

# 判断是否有一方胜出
def isWin(q):
    # 遍历每一种胜出的条件
    if nine[0][0] == q and nine[0][1] == q and nine[0][2] == q:
        drawWin(q)
    elif nine[1][0] == q and nine[1][1] == q and nine[1][2] == q:
        drawWin(q)
    elif nine[2][0] == q and nine[2][1] == q and nine[2][2] == q:
        drawWin(q)
    elif nine[0][0] == q and nine[1][0] == q and nine[2][0] == q:
        drawWin(q)
    elif nine[0][1] == q and nine[1][1] == q and nine[2][1] == q:
        drawWin(q)
    elif nine[0][2] == q and nine[1][2] == q and nine[2][2] == q:
        drawWin(q)
    elif nine[0][0] == q and nine[1][1] == q and nine[2][2] == q:
        drawWin(q)
    elif nine[2][0] == q and nine[1][1] == q and nine[0][2] == q:
        drawWin(q)
    # 平局
    elif number == 9 :
        drawDraw()
    else:
        return False
# 胜出一方提示 
def drawWin(q):
    if q == 1:
        font = pygame.font.Font('BankgothicMB.ttf', 45)
        text = font.render('Circle WIN!!!', True, RED)
        screen.blit(text, (210, 300))
    elif q == 2:
        font = pygame.font.Font('BankgothicMB.ttf', 45)
        text = font.render('X WIN!!!', True, RED)
        screen.blit(text, (260, 300))
# 平局提示
def drawDraw():
    font = pygame.font.Font('BankgothicMB.ttf', 40)
    text = font.render('THE GAME HAS DRAWN!', True, RED)
    screen.blit(text, (85, 300))


while True: # 程序主循环
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        elif event.type == MOUSEBUTTONDOWN:
            pos = pygame.mouse.get_pos()
            # 判断鼠标点击在哪个格子上
            x = (pos[0]-50) // 200
            y = (pos[1]-50) // 200

            # 筛选掉已经下过的格子
            if nine[x][y] == 0 and status == 1 :
                # 画圈
                pygame.draw.arc(screen, GREEN,[x*200+75,y*200+75, 150, 150], 0, 2*pi, 5)
                nine[x][y]=1
                number +=1
                # 当下到第五颗棋时开始判断是否有一方胜出
                if number>4:
                    isWin(1)
                status = 0
            # 叉方，逻辑同上
            elif nine[x][y] == 0 and status == 0 :
                # 画叉
                pygame.draw.line(screen, BLUE, [x*200+75, y*200+75], [x*200+225, y*200+225], 6)
                pygame.draw.line(screen, BLUE, [x*200+225, y*200+75], [x*200+75, y*200+225], 6)
                nine[x][y]=2
                number +=1
                if number>4:
                    isWin(2)
                status = 1
            else :
                pass

    pygame.display.update()# 绘制屏幕内容