??????用于从ftp删除旧文件的Linux shell脚本

由于实际工作中遇到客户现场紧急停电，发现linux系统上有脚本丢失情况，客户要求按时备份应用代码，并定时删除旧文件，客户仅提供一个FTP容量可供备份。

之前写过类似FTP文件上传备份脚本，当时无法满足要求
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#/bin/bash
#本地目录
localdir="/opt/Oracle/....../logs";

#目标目录
targetdir="/test";

#临时目录
tempdir="/opt/backuptmp";

#把一天内的日志复制到临时目录,1>/dev/null 2>&1不输出错误信息
find $localdir -mtime -1 -name "*" -exec cp -f {} $tempdir \;

#标识成对
ftp -v -n <<EOF
open 10.1.111.111
user ftp用户名 ftp密码
binary
hash
cd $targetdir
lcd $tempdir  --切换本地计算机上的目录
prompt --切换提示不显示
mput *
bye
#here document
EOF
echo "commit to ftp successfully"
cd $tempdir
rm -rf $tempdir/*

查看类似帖子，发现有相关示例：
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#!/bin/bash 
# get a list of files and dates from ftp and remove files older than ndays 
ftpsite="ftp.yourserver.com" 
ftpuser="loginusername" 
ftppass="password" 
putdir="/public_ftp/admin/logs" 

ndays=7 


# work out our cutoff date 
MM=`date --date="$ndays days ago" +%b` 
DD=`date --date="$ndays days ago" +%d` 


echo removing files older than $MM $DD 

# get directory listing from remote source 
listing=`ftp -i -n $ftpsite <<EOMYF 
user $ftpuser $ftppass 
binary 
cd $putdir 
ls 
quit 
EOMYF 

lista=($listing) 

# loop over our files 
for ((FNO=0; FNO<${#lista[@]}; FNO+=9));do 
    # month (element 5), day (element 6) and filename (element 8) 
    #echo Date ${lista[`expr $FNO+5`]} ${lista[`expr $FNO+6`]}   File: ${lista[`expr $FNO+8`]} 

    # check the date stamp 
    if [ ${lista[`expr $FNO+5`]}=$MM ]; 
    then 
    if [[ ${lista[`expr $FNO+6`]} -lt $DD ]]; 
    then 
     # Remove this file 
     echo "Removing ${lista[`expr $FNO+8`]}" 
     ftp -i -n $ftpsite <<EOMYF2 
     user $ftpuser $ftppass 
     binary 
     cd $putdir 
     delete ${lista[`expr $FNO+8`]} 
     quit 
EOMYF2 


    fi 
    fi 
done

进供参考。
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